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If X is a continuous random variable, argue that P(x, SXS x₂) = P(x₁ < X < x₂) = P(x₁ < X < x₂) = P(x₁ < X < x₂). O Because the probabilities P(X= x₁). P(X= x2) are approximately equal to zero, all the probabilities listed are equal. O These probabilities are not equal. O Because the probabilities P(X= x₁) = P(X=x₂)=0, all the probabilities listed are equal. f(x) dx the function /f(x) in any of the endpoints x; and ay is always equal to zero, all the Because in the integral probabilities listed are equal.

If X is a continuous random variable, argue that P(x, SXS x₂) = P(x₁ < X < x₂) = P(x₁ < X < x₂) = P(x₁ < X < x₂). O Because the probabilities P(X= x₁). P(X= x2) are approximately equal to zero, all the probabilities listed are equal. O These probabilities are not equal. O Because the probabilities P(X= x₁) = P(X=x₂)=0, all the probabilities listed are equal. f(x) dx the function /f(x) in any of the endpoints x; and ay is always equal to zero, all the Because in the integral probabilities listed are equal.

Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter7: Distance And Approximation
Section7.3: Least Squares Approximation
Problem 31EQ
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If X is a continuous random variable, argue that Px₁ ≤X ≤ x₂) = P(x₁ < X ≤ x₂) = P(x₁ < X < x₂) = P(x₁ < X < x₂). O Because the probabilities P(X= x₁). P(X= x₂) are approximately equal to zero, all the probabilities listed are equal. O These probabilities are not equal. O Because the probabilities P(X= x₁) = P(X= x₂) = 0, all the probabilities listed are equal. O Because in the integral S(x) dx the function f(x) in any of the endpoints.x, and x2 is always equal to zero, all the probabilities listed are equal.
Transcribed Image Text:If X is a continuous random variable, argue that Px₁ ≤X ≤ x₂) = P(x₁ < X ≤ x₂) = P(x₁ < X < x₂) = P(x₁ < X < x₂). O Because the probabilities P(X= x₁). P(X= x₂) are approximately equal to zero, all the probabilities listed are equal. O These probabilities are not equal. O Because the probabilities P(X= x₁) = P(X= x₂) = 0, all the probabilities listed are equal. O Because in the integral S(x) dx the function f(x) in any of the endpoints.x, and x2 is always equal to zero, all the probabilities listed are equal.
In Applied Life Data Analysis (Wiley, 1982), Wayne Nelson presents the breakdown time of an insulating fluid between electrodes at 34 kV. The times, in minutes, are as follows: 0.28, 0.88, 0.97, 1.29, 2.65, 3.16, 4.14, 4.80, 4.88, 6.37,7.22,7.95, 8.33, 11.98, 31.84, 32.41, 33.97, 36.84, and 72.75. Construct a normal probability plot of these data. Does it seem reasonable to assume that breakdown time is normally distributed? Choose the correct answer. O Yes, breakdown time is normally distributed. O No, breakdown time is not normally distributed.
Transcribed Image Text:In Applied Life Data Analysis (Wiley, 1982), Wayne Nelson presents the breakdown time of an insulating fluid between electrodes at 34 kV. The times, in minutes, are as follows: 0.28, 0.88, 0.97, 1.29, 2.65, 3.16, 4.14, 4.80, 4.88, 6.37,7.22,7.95, 8.33, 11.98, 31.84, 32.41, 33.97, 36.84, and 72.75. Construct a normal probability plot of these data. Does it seem reasonable to assume that breakdown time is normally distributed? Choose the correct answer. O Yes, breakdown time is normally distributed. O No, breakdown time is not normally distributed.
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