If X=(A+B+C+D')(A+B+C'+D')(A+B'+C+D') (A+B'+C'+D')and Y=A'B'+ABD. Then Z=XY can be written in a simplest SOP form as Z=A+D' Z=A'B' Z=ABD+A'B'D Z=ABD+A'B'D'

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A: Simplified the given boolean expression

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A: Part a) =========

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A: Here is the solution with an output:-

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A: Obtain expression for POS form:

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A: Polynomial A: Polynomial B: Polynomial c :   Polynomial D:

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A: Polynomial A:

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A: Answer is in step2.

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A:

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A:

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A:

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A: EXPLANATION: The complement for any set contains all the elements that are present in the universal…

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A:

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A: Answer  : option " c " is correct answer  F = z' + xy'

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A: Answer ;

Q: L = {x1#x2#x3 | X1, x2, X3 E {0, 1}*, and for some i and j e {1,2, 3}, i # j, x¡ = x %3D

A: The answer is

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A: Step 1 The solution is given in the below step;

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A:

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A:

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A: The Answer is

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A:

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A:

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A: The Answer is

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A: This code works fine in less as you said.

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A: Note: As per the guidelines, we are supposed to answer one full question, please repost other…