Simplify the function F represented by the following Kmap into the simplest SOP expression: АВ 00 01 11 10 CD 00 1 1 01 1 11 10 1 Select one: Oa. F B'D' ABC A'CD Ob. F= CD ABC+ A'CD - AB CD O C. F= CD ABC + A'CD AB'D' Od. F= CD ABC A'CD 1,
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- Implement the following Boolean function using a multiplexer. Use A, C and D as the select lines, where A is the MSB and D is the LSB. Answer the following questions. Include a systematic solution for you answer, if applicable.1. Which of the following inputs are not connected to the ground?A. I2B. I5C. I6D. More than one of the choicesE. None 2. Which of the following inputs are connected to B?A. I0B. I1C. I3D. More than one of the choicesE. None 3. Which of the following inputs are connected to +5V or Vcc?A. I3B. I4C. I7D. More than one of the choicesE. None 4. What is the output when A=1, B=0, C=1 and D=0?A. +5VB. 0VC. B’D. More than one of the choicesE. NoneGiven an infix expression a*(b+c)-d, its postfix expression is (A) a b c d * + - (B) a b c + * d - (C) a b c * + d - (D) - + * a b c d Which is the right answer and please explain whySimplify the following Boolean expressions, using four-variable maps: (a) A'B'C'D' + AC'D' + B'CD' + A'BCD + BC'D (b) x'z + w'xy' + w(x'y + xy') (c) A'B'C'D + AB'D + A'BC' + ABCD + AB'C
- Implement the psueodocode in assembely language. use short-circuit evalution where appropriate and assume all variables are 32-bit signed integers. eax = X ebx = A edx = B while (X >= 0) if(((X < B) AND (A != 3)) OR (( X > A) AND (B<A))) X = X+A else X = X+B end whileC++ Program: Make a program that would demonstrate the concept of Line Coding: Bipolar Pseudoternary if next bit is 0, there is inversion if next bit is 1, no inversion and output is zero Input: 1 1 1 0 0 1 0 1 1 0 0 0 Output: zero zero zero pos neg zero pos zero zero neg pos negWhat is F in SOP in expression F(w,x ,y z) = Σ(2, 4, 6, 8, 10, 12): d(0, 1, 3, 5, 7, 9, 11, 13, 14, 15) a. 1 b. F = (wx) + (yz) c. F = (xyz) + (wz) + (yz) d. F = (wy) + (xz)
- Construct a pushdown automaton which accepts the set of bit strings with 2/3 as many 0 bits as 1 bits. (For example, 10110 should be accepted, since there are three 1s and two 0s, and two is 2/3 of three.)4. Simplify the following Boolean expressions, using four-variable K-maps: (a) A′B′C′D′+AC′D′+B′CD′+A′BCD+BC′D (b) w′z+xz+x′y+wx′zSimplify the following expression using K Mapping Y = B~C~D+AB~C+A~CD+A~BD+~AB~D
- Not handwritten For each of the following CFGs and string w, convert the CFG into an equivalent PDA e.) E → E +T | T T → T * F | F F → P ^ F | P P → (E) | a | b w = b + a * (a + b) ^ a * bIn cyclic redundancy checking, if g(x) =1011, d(x)= 0100, and the remainder to be 111, what is the codeword c(x) a. 1011111 b.0100111 c. 10110100 d.01001011 e. 1011 f. 0100 g. 111For function F(a,b,c) = ∑[sum symbol] m(1,3,4,6), which one is equal to F in POS form? A ) F(a,b,c) =(a'.b'.c') + (a'.b.c')+ ( ab'c )+( abc ) B ) F(a,b,c) =(a'+b'+c').(a'+b+c') (a+b'+c')(a+b+c) C ) F(a,b,c) =(a+b+c).(a+b'+c) (a'+b+c')(a'+b'+c') D ) F(a,b,c) =(a.b.c) + (a.b.c)+ (a'bc')+(a'b'c')