If (xcos(y) – y)dx + (xsin(y) + x)dy = 0 is not exact. %3D .A false .B True

Q: /3 2 %3D

A: To find: The value of dydx. Given: The equation is y=x35x2+1-23. Formula used: Chain rule of…

Q: 7x? +6 Find dy for y = X 7x -6 dy =

A: Given that, y=7x2+6x Differentiating with respect to x we get,

Q: syidr + [2yłn () + 3siny]dy: 6. x²+3x 3y?dx 5x ;when x = 1, y = 0 x+3,

A: Given, Differential Equation:  3y2x2+3xdx+2y ln5xx+3+3 sin ydy=0when, x=1 and y=0 To find: The…

Q: 4x Compute (2x + 4yz) dz dæ dy 1

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Q: If y = Vu+2 and u = 4x - 2, then dy/ dx is 1 (A) 1 B 4x3/2 1 (D x+1

A: We have to find

Q: (у*- 2ху)dx + Зx*dy %3D 0 Nhen y 3D 1, х — 2 ||

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Q: Ɔ) = 1, the solu %D dy + 4 + 4 dx

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Q: Obtain the general solution to the equation. dy y +7x +1 %3D dx

A: Here we have to find general solution of given differential equation

Q: (2х — 3)* y = - х +1 .2 х*у + 3ху3 — х %3D 3 X =

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Q: 4.x?y³. dx = xyt + 2 4x2,3 dy 4

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Q: dy if 4x² + 4y? = In (xy) dx %3D dy dx

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Q: Given y+In(-) = e dy then dx x(y+1)

A: Given: y+lnyx=e We know that ddxuv=vdudx-udvdxv2                                                 ..1

Q: 3. Find the dy/dx of * y? + 2x – 3y = 0

A: The given function,         y2+2x-3y=0

Q: Bernoulli dy + xy = dx y # 0 уз

A: The objective is to find the general solution to the given differential equation

Q: What's the general solution : (y − 1) (dy/dx) = y(x^2)

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Q: 1. Given: y = 2x - Find: a.) dy/dx b.) y"

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Q: Find dy/dx If y ex A 2/א"e ],/איe D-2V B.

A: We have to find dy/dx.

Q: If y=x^2 e^2x then dy/dx is equal to

A: we have,y=x2e2xdifferentiating both the sides w.r.t. xusing product rule,we…

Q: (x** ye) dx + zy dy

A: To Solve for the general solution of the following first order differential equations.

Q: 1) S , (x + y) dx dy

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Q: 15. In (x² + y² + 1) dx dy

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Q: .3 9. dx dy y2

A: Find the double integration.

Q: , 4cosx dx dy

A: First draw the region of integration. Then, use the region of integration to change the order .…

Q: y^2 dy/dx = 4 is:

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Q: Find the dy/dx: Given y = 3x +2x-1

A: solution:-y=f(x)=3x2+2x-1f(x+h)=3(x+h)2+2(x+h)-1             =3x2+2xh+h2+2(x+h)-1…

Q: what is the order and degree of the equation:   (d^3y/dx^3)^2/3 = x+6 dy/dx

A: Given that: d3ydx323=x+6dydx

Q: Answer the given DE below: x (dy/dx) +y=y^2

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Q: I[ Tv° dz dy = x dx dy = y? x dx y dy

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Q: dy/dx + 2xy + xy = 0 Ans. 1/y3 = -;+ 1 + ce3x? 2

A: The given differential equation is  dy/dx + 2xy +xy4=0

Q: x³ex? (Xie, 2010) y In y dy 2. dx

A: Given query is to find the solution of the differential equation using seperation variable.

Q: Find​ dy/dx by differentiating implicitly. When​ applicable, express the result in terms of x and y.…

A: Given : 5x+7y=3

Q: C. dy b. 4 sin 2x> , y = 2, when x = 2 %3D dx dy С. dx = x + 3+ e2x>, y = -1, when x =

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Q: dy If y = x (e* - 1), then %3D 6. dx

A: Given: y=x^2 ((e^ x)-1) To determine: d y/dx

Q: 2 6x? Find dy for y = x? 6x + 7 dy =

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Q: If yx^2 + y^2 = x, then the dy/dx is

A: Using derivatives formula.

Q: If we solve the DE y dx + 2 x dy 0 alter converting it to Exad using an

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Q: If x t-t3 and y = t2-t, the value of at t = 2 is dy dx

A: It is simple differentiation.

Q: If x u(u – 1)2 and y = (3u - 1)², then what is the value of dy/dx

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Q: If y= In(3x² – 6x – 8), then find dy. | dx

A: Chain Rule of Differentiation dydx=dydududx................................................(A)…

Q: A. (x+1)* -y? ) dy dx

A: To solve (a) only Ques (a) : ((x+1)²-y²)dy/dx -(2(x+1)y-10(x+1)²)=0

Q: If 3x² + 2xy + y² = 2, then the value of dy/dx at x = 1 is

A: Given that        3x2+2xy+y2= 2 We have to find the value of dy/dx at x=1.

Q: In(y? + 1)dx +2dy 0 y2+1

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Q: Given the IVP dy + 4y = x - 2, y(1) = 0, dx the value of y(2) is closest to

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Q: Find dy If y=1-t and x2 dx

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Q: M                   dy/dx - y = e^x y^2

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Q: Find if y = e*² · 6* %3D dx

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Q: NOTE: Enter the exact answer. yz dx dz dy = %3D -90

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Q: 1- y? 1+ y 4 06: If x? dx Show that 1 %3D ,2 dy レアス+1.

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Rate of Change

The relation between two quantities which displays how much greater one quantity is than another is called ratio.

Slope

The change in the vertical distances is known as the rise and the change in the horizontal distances is known as the run. So, the rise divided by run is nothing but a slope value. It is calculated with simple algebraic equations as: