If you haven't already done so, distribute the A to the x – 1 and the B to the x + 3 in the equation from the previous slide, 5 = A(x – 1)+B(x + 3) Submit the new equation below. Try again. 5 = (A+ B)x + (3B – A) |

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.3: The Natural Exponential Function
Problem 43E
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Example 2 (Slide 3 of 5)
If you haven't already done so, distribute the A to the
x – 1 and the B to the x + 3 in the equation from the
previous slide,
5 = A(x – 1)+B(x +3)
Submit the new equation below.
Try again.
5 = (4 + B)x + (3B – A)
Transcribed Image Text:Example 2 (Slide 3 of 5) If you haven't already done so, distribute the A to the x – 1 and the B to the x + 3 in the equation from the previous slide, 5 = A(x – 1)+B(x +3) Submit the new equation below. Try again. 5 = (4 + B)x + (3B – A)
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