If you know the uncertainty in position (ΔΔx ) is 100nm, what is the lowest velocity uncertainty ( ΔΔv ) we could measure for an electron (in m/s). (mass of an electron 9.109x10-31 kg)
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If you know the uncertainty in position (ΔΔx ) is 100nm, what is the lowest velocity uncertainty ( ΔΔv ) we could measure for an electron (in m/s). (mass of an electron 9.109x10-31 kg)
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- The uncertainty in the velocity V of a moving electron of mass 10−4010−40 kg is 2 x106m/s2 x106m/s . Calculate the uncertainty of the simultaneous measurement of its position X. [Take 6.63 x10−346.63 x10−34 ]A bird flies a distance of d = 150±3 m during a time t = 20.0±1.0 s. The average speed of the bird is v = d/t = 7.5 m/s. What is the uncertainty of v?The diameter of a Hydrogen atom is about 10.6 nm. What is the minimum uncertainty in momentum of an electron along this diameter if it's uncertainty in position is equal to the diameter of the atom? a) 1.17 x 10^-25 kgm/s b)9.94 x 10^-26 kgm/s c)1.17x10^-26 kgm/s d) 9.94x10^-27 kgm/s e)