If 351 mL of N2 at 34.7 oC and 653 torr is allowed to expand to 850 mL and 605 torr, what is the new temperature (°C)?

Introductory Chemistry For Today
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ISBN:9781285644561
Author:Seager
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Chapter6: The States Of Matter
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Problem 6.43E
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If 351 mL of N2 at 34.7 oand 653 torr is allowed to expand to 850 mL and 605 torr, what is the new temperature (°C)?

Expert Solution
Step 1

Here given,

Initial volume (V1) = 351 mL = 0.351 L

Initial pressure (P1) = 653 torr = 0.8592 atm

Initial temperature (T1) = 34.70C = (273+34.7) K = 307.7 K

Final volume (V2) = 850 mL = 0.85 L

Final pressure (P2) = 605 torr = 0.796 atm

Final temperature (T2) =?

We know, the formula---

P1 V1 / T1 = P2 V2 / T2 

Or, T2 = (P2 V2 T1) / (P1 V1)

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