Please Help 120CHM 1025L: Post-laboratory Assignment for Limiting Reactant1.A student adds 25.27 ml. of a 0.250 M Na;SO4 solution to another solution containing2.00 grams of BaCla solid (dissolved). Given the following unbalanced equation, whatmass of precipitate (BaSO) should have been formed, based on the limiting reactant?BaCl2 (aq) + _Na2SO4 (aq) →_BaSO4 (s) + NACI (aq)v toll Daz soys s.27 hbn of Nazsoyweigho Baclz 2.so gmmuve Nazsoye 0.150 × 2s.2a0.75 M-0.0184shole Bacla :Bad> 2.5ognBadz: 0.012o mores6.0120 boT x Z33.30egibrot2.80 gy2. A student adds 250. mL of deionized water (H2O) to a sample containing 75.00 grams ofsodium solid. Given the following unbalanced equation, what mass of sodium hydroxideshould have been formed, based on the limiting reactant? Given: the density of water atroom temperature is 0.998 g/mL. First, please balance the reaction. HINT: Since wateris not a solution, molarity does not apply. Water is a pure liquid, and you’ll need to usethe density to first convert volume to mass._H2 (g)2 Na (s) + 2 H2O (1) → 2 NAOH (aq) +Reacoion:z mol itzomuss Gf Na 125.0ogaso omL5.427 heレtax:s.437 moi HzoVolume HzO :Density of HzO :6.998 g mneDa- lim. Reac Quna:S.437 mal५9.58)moles = 22.99$/mol.13.8s holT8.02 g/molmules at NaoHmm: 40.0gmolmuss of Daot prouluced :5.437 bnot x 4ougsaol:Cマ.5g pa円Muss Ne - 12s.00gA lomic mus 3:22.49g Imulmoles of Na = 2s.00g6.437)nol 119TRIAL 2: Using either Option 1 or Option 2 in the sample calculations, determine both uhetheoretical yield of NaCl in your reaction for trial 2, and indicate which reactant (HCI or NazCO3)was the limiting reactant.Dae CosTheoretical Yield of NaCl, Trial 2Limiting Reactant for Trial 2Considering the mass of residue you actually recovered in trial 2, what was the percent yield ofthis reaction?Percent Yield of NaCl (trial 2)Error Analysis - TRIAL 2Comment briefly on why you think your percent yield was not 100%. If your percent yield wasgreater than 100%, what other substance(s) may have been present in the residue? If your percentyield was less than 100%, what may have happened to the NaCl product?

Answered: Image /qna-images/answer/99aaf74b-96bf-4f81-a638-26244aed2266.jpg

Ignment for Limiting Reactant 1. A student adds 25.27 mL of a 0.250 M Na;SO, solution to another solution containing 2.00 grams of BaClh solid (dissolved). Given the following unbalanced equation, what mass of precipitate (BasO,) should have been formed, based on the limiting reactant? BaCla (ag)

Ignment for Limiting Reactant 1. A student adds 25.27 mL of a 0.250 M Na;SO, solution to another solution containing 2.00 grams of BaClh solid (dissolved). Given the following unbalanced equation, what mass of precipitate (BasO,) should have been formed, based on the limiting reactant? BaCla (ag)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter13: Chemical Equilibrium

Section: Chapter Questions

Problem 128IP: The hydrocarbon naphthalene was frequently used in mothballs until recently, when it was discovered...

See similar textbooks

Similar questions

Calculate rH for the reaction 2 C(s) + 3 H2(g) + O2(g) C2H5OH() given the information below. C(s) + O2(g) CO2(g) rH = 393.5 kJ/mol-rxn 2 H2(g) + O2(g) 2 H2O() rH = 571.6 kJ/mol-rxn C2H5OH() + 3 O2(g) 2 CO2(g) + 3 H2O() rH= 1367.5 kJ/mol-rxn
The hydrocarbon naphthalene was frequently used in mothballs until recently, when it was discovered that human inhalation of naphthalene vapors can lead to hemolytic anemia. Naphthalene is 93.71% carbon by mass, and a 0.256-mole sample of naphthalene has a mass of 32.8 g. What is the molecular formula of naphthalene? This compound works as a pesticide in mothballs by. sublimation of the .solid so that it fumigates enclosed spaces with its vapors according to the equation Naphthalene(s)naphthalene(g)K=4.29106(at298K) If 3.00 g solid naphthalene is placed into an enclosed space with a volume of 5.00 L at 25C, what percentage of the naphthalene will have sublimed once equilibrium bas been established?
The following reaction occurs in pure water: H2O(l)+H2O(l)H3O+(aq)+OH-(aq) which is often abbreviated as H2O(l)H+(aq)+OH-(aq) For this reaction, G = 79.9 kJ/mol at 25C. Calculate the value of G for this reaction at 25C when [OH] = 0.15 M and [H+] = 0.71 M.
What characterizes an electrolytic cell? What is an ampere? When the current applied to an electrolytic cell is multiplied by the time in seconds, what quantity is determined? How is this quantity converted to moles of electrons required? How are moles of electrons required converted to moles of metal plated out? What does plating mean? How do you predict the cathode and the anode half-reactions in an electrolytic cell? Why is the electrolysis of molten salts much easier to predict in terms of what occurs at the anode and cathode than the electrolysis of aqueous dissolved salts? What is overvoltage?
9.96 Most first aid "cold packs" are based on the endothermic dissolution of ammonium nitrate in water: NH4NO3(s)NH4+(aq)+NO3(aq) H= 25.69 kJ A particular cold pack contains 50.0 g of NH4NO3 and 125.0 g of water. When the pack is squeezed, the NH4NO3dissolves in the water. If the pack and its contents are initially at 24.0°C, what is the lowest temperature that this bag could reach? (Assume that the ammonium nitrate solution has a specific heat of 4.25J g-l K-l, and that the heat capacity of the bag itself is small enough to be neglected.)
Sodium chloride is added to water (at 25C) until it is saturated. Calculate the Cl concentration in such a solution. Species G(kJ/mol) NaCl(s) 384 Na+(aq) 262 Cl(aq) 131
Given that the Gf for Pb2+(aq) and Cl-(aq) is -24.3 kJ/mole and -131.2 kJ/mole respectively, determine the solubility product, Ksp, for PbCl2(s).
12.67 Hydrofluoric acid is a weak acid used in the building industry to etch patterns into glass for elegant windows. Because it dissolves glass, it is the only inorganic acid that must be stored in plastic containers. A 0.1 M solution of HF has a pH of 2.1. Calculate [Hj0"| in this solution.
For a precipitation reaction to be useful in a gravimetric analysis, the product of the reaction must be insoluble. Is Kc1,1 or 1 for a useful precipitation reaction?
Table 17-1 lists common half-reactions along with the standard reduction potential associated with each half-reaction. These standard reduction potentials are all relative to some standard. What is the standard (zero point)? lf is positive for a half-reaction, what does it mean? If is negative for a half-reaction, what does it mean? Which species in Table 17-1 is most easily reduced? Least easily reduced? The reverse of the half-reactions in Table 17-1 are the oxidation half-reactions. How are standard oxidation potentials determined? In Table 17-1, which species is the best reducing agent? The worst reducing agent? To determine the standard cell potential for a redox reaction, the standard reduction potential is added to the standard oxidation potential. What must be true about this sum if the cell is to be spontaneous (produce a galvanic cell)? Standard reduction and oxidation potentials are intensive. What does this mean? Summarize how line notation is used to describe galvanic cells.
__C₅H₁₂ + __O₂ --> __H₂O + __CO₂ To balance the attached reaction, what coefficient needs to be put in front of the H₂O?
Consider two solutions, the first being 50.0 mL of1.00 M CuSO4 and the second 50.0 mL of 2.00 M KOH.When the two solutions are mixed in a constant-pressurecalorimeter, a precipitate forms and the temperature of themixture rises from 21.5 to 27.7 °C. (a) Before mixing, howmany grams of Cu are present in the solution of CuSO4?(b) Predict the identity of the precipitate in the reaction.(c) Write complete and net ionic equations for the reactionthat occurs when the two solutions are mixed. (d) From thecalorimetric data, calculate ΔH for the reaction that occurson mixing. Assume that the calorimeter absorbs only a negligiblequantity of heat, that the total volume of the solutionis 100.0 mL, and that the specific heat and density of thesolution after mixing are the same as those of pure water.