Question
Asked Oct 12, 2019
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II
2.4.15
Solve the right triangle.
p
n
53.50
P
127 m
M=
(Round to one decimal place as needed.)
m (Round to the nearest integer as needed.)
m (Round to the nearest integer as needed.)
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II 2.4.15 Solve the right triangle. p n 53.50 P 127 m M= (Round to one decimal place as needed.) m (Round to the nearest integer as needed.) m (Round to the nearest integer as needed.)

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Expert Answer

sinx=p/h and co...

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angle M-36.5 degree now sin53.5=.80 whil ecos 53.5=59 127 so p 216 59 and n-80x216-172.8

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