(II) A parallel-plate capacitor has fixed charges +Q and –Q. The separation of the plates is then halved. (a) By what factor does the energy stored in the electric field change? (b) How much work must be done to reduce the plate sepa- ration from d to d? The area of each plate is A.
(II) A parallel-plate capacitor has fixed charges +Q and –Q. The separation of the plates is then halved. (a) By what factor does the energy stored in the electric field change? (b) How much work must be done to reduce the plate sepa- ration from d to d? The area of each plate is A.
Chapter8: Capacitance
Section: Chapter Questions
Problem 70AP: A parallel-plate capacitor with capacitance 5.0F is charged with a 12.0-V battery, after which the...
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![(II) A parallel-plate capacitor has fixed charges +Q and –Q.
The separation of the plates is then halved. (a) By what
factor does the energy stored in the electric field change?
(b) How much work must be done to reduce the plate sepa-
ration from d to d? The area of each plate is A.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9fd06d49-08c1-4c69-9a5c-c5b264d85373%2F1fbfe46c-05b8-4413-b4a1-2fdc0f56c15a%2Fqwb3px.png&w=3840&q=75)
Transcribed Image Text:(II) A parallel-plate capacitor has fixed charges +Q and –Q.
The separation of the plates is then halved. (a) By what
factor does the energy stored in the electric field change?
(b) How much work must be done to reduce the plate sepa-
ration from d to d? The area of each plate is A.
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