(II) A person of mass 75 kg stands at the center of a rotatingmerry-go-round platform of radius 3.0 m and moment ofinertia 820  kg .m2 The platform rotates without frictionwith angular velocity 0.95 rad/s The person walks radiallyto the edge of the platform. (a) Calculate the angularvelocity when the person reaches the edge. (b) Calculatethe rotational kinetic energy of the system of platform plusperson before and after the person’s walk.

Q: (III) Suppose a 65-kg person stands at the edge of a 5.5-mdiameter merry-go-round turntable that is…

A: Given: Mass of the person = 65 Kg The diameter of the merry go round turntable = 5.5 m Moment of…

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A: Given Mass m=9kgαAB=3αAB i-2αAB j A=acceleration of mass at G

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A: (a)

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A:

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A: Given data Mass of the rods, m=15 g=0.015 kg Length, L=30 cm=0.3 m Angular velocity of the center of…

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A: Angular frequency, ω1 = 0.25 rev/s Angular frequency, ω2 = 0.80 rev/s Ratio of moment of inertia,…

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A: Moment of inertia of first disk (I1) = 1.09 kg-m2Moment of inertia of second disk (I2) = 9.58…

Q: When the axis of rotation of a body changes does moment of inertia also change? Why?

A: Step 1The moment of inertia of a body is directly proportional to the mass of the body and the…

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A:

Q: The 9-kg slender bar AB is released from rest in the position shown. Neglect friction in all contact…

A:

Q: Find the moment of force of 30N about an axis of rotation at distance 0.5m from the force.

A: Given Data:- The force is f = 30N The distance of the force from axis of rotation is d = 0.5m.

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A: Solution: The schematic diagram of the system is as shown below:

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A:

Q: = 40cm is allowed to spin on a A thin cylindrical wheel of radius r= frictionless axle. The wheel,…

A: Here, the torque can be obtained as τ=rF sinθ=40×10-2 m50N sin90°=20Nm

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A:

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A: SOlution: Given that r = 2i-3j m v = 4i m/s m = 1.5 kg

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A: According to the data provided

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A:

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A:

Q: I need help solving this problem!

A: The moment of inertia is calculated as

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A: