II. Read each problem carefully and present an algorithm with the required running-time to solve eachproblem.2. Let A be a sorted array of n integers. You want to implement two functions:update (i, x) - which takes as input an index i in A and sets A[i] = x. For example, callingupdate (3,10) will set A[3] = 10. Note that array A might not be completely sorted after anupdate.is Sorted (i) - returns true if the subarray A[0... i] is sorted, otherwise it returns false.A straightforward implementation of the two operations using only the given array can be doneas follows:update operation can directly change the value of A[i] to x.is Sorted will scan A[0] up to A[i] while checking if elements are non-decreasing.With the above implementations, update takes O(1) time but is Sorted takes O(n) time.a. Give another implementation where update takes O(n) time while isSorted takes O(1) time.

Answered: a. Give another implementation where…

Engineering

Computer Science

a. Give another implementation where update takes O(n) time while isSorted takes 0(1) time.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

1) Consider an integer array a of length n with indexing starting at 0, where n is a positive integer.If the elements of array a are to be written out in reverse order, which of the following C++ code fragment does NOT do the job? Question options: a. int i=n-1; while (i>=1){cout << a[i] << endl; i = i-1;} cout << a[i] << endl; b. int i=n-1; while (i>=1){cout << a[i] << endl; i = i-1;} c. int i=n-1; while (i>=0){cout << a[i] << endl; i = i-1;} d. int i=n; while (i>0){cout << a[i-1] << endl; i = i-1;} 2) Assume we use 8-bit cell to store floating point numbers, 1 bit for sign, 3 bits for excessed exponent, and 4 bits for significand. What is the decimal value for a cell with bit pattern 0 111 1101 Question options: a. 125 b. 224…
Given an array A = [10, 7, 4, 2, 1], and target = 7, return the index of the target if found, else return -1. 1. Can this problem be solved in O(logN)? 2. If so, write the implementation. Mention time and space complexity 3. If this problem cannot be solved using O(logN), what is the solution that you suggest - write the code and also mention time and space complexity.
Modify the Partition function so that after running it, any input array A is partitioned into three parts: the left part consisting of all elements < pivot, the middle part consisting of all elements = pivot, and the right part consisting of the rest Write down the pseudo-code for this modified version of the Partition function. (must be an in-place algorithm with Θ(n) time complexity.) Hint: Define three indices: i as the end of the left part, k as the end of the middle part, and j denoting the current index which is used in the for-loop.
You want to design an algorithm, called minMax(A,p,r), that takes an array of integers and indexes of the first and last elements, and returns the minimum and maximum values in that range. Now write the pseudo code of a divide and conquer (and therefore, recursive) algorithm with the same time complexity (Θ(n)). You can assume that p ≤ r. Also, in your code, you can return two numbers by returning a pair, e.g. “return (a, b)”, and can save the output in a similar way, e.g. “(a, b) = minMax(parameters)”. (Short answer please)
The drawback of this approach, is that with each recursive function call, we only reduce the size of the array by one element, and we use a storage space for one activation record. A faster approach is, with each recursive call, reduce the size of the array by 3 elements. a. Write a reduce-and-conquer recursive function FastRecSum()(C++ or python) that find the sum of all float (real) elements in an array of size n. b. Using addition of float (real) values as a basic operation, set up and solve a recurrence relationship to compute the complexity of your code, as a function of the size n of the array.
Implement a range function for a dynamic array which returns a new dynamic array that is a subset of the original. input parameters: array - (the array and any related parameters) start - index of the first elementend - index of the last elementInterval - An integer number specifying the incrementation of index This function returns a new dynamic array containing the elements from the start thru the end indices of the original array.All array indexing must be done using pointer arithmetic. For example, given the array: 49 96 99 47 76 29 22 16 30 22 If the start and end positions were 5 and 9 with step 2, return a new dynamic array: 29 16 22 Please use following main to test your function. int main(){int *p = new int[10]{49,96,99,47,76,29,22,16,30,22}; int *q = range(p,10,5,9,2);for(int i=0;i<3;i++) cout<<q[i]<<" "; // print 29 16 22 cout<<endl;delete [] q;q = range(p,10,1,8,3); for(int i=0;i<3;i++)cout<<q[i]<<" "; // print 96 76 16 cout<<endl;…
Write a Python function def isSubArray(A,B) which takes two arrays and returns True if the first array is a (contiguous) subarray of the second array, otherwise it returns False. You may solve this problem using recursion or iteration or a mixture of recursion and iteration. For an array to be a subarray of another, it must occur entirely within the other one without other elements in between. For example: [31,7,25] is a subarray of [10,20,26,31,7,25,40,9] [26,31,25,40] is not a subarray of [10,20,26,31,7,25,40,9] A good way of solving this problem is to make use of an auxiliary function that takes two arrays and returns True if the contents of the first array occur at the front of the second array, otherwise it returns False. Then, A is a subarray of B if it occurs at the front of B, or at the front of B[1:], or at the front of B[2:], etc. Note you should not use A == B for arrays.
implement QuickSort of ints that sorts the numbers in the non-decreasing order and in c language Implement the rearrange function used for QuickSort using the O(n) time algorithm with two pointers. The function gets as input an array, and index of the pivot. The function rearranges the array, and returns the index of the pivot after the rearrangement. please write form as: int rearrange(int* A, int n, int pivot_index); 2, Implement the QuickSort algorithm. For n<=2 the algorithm just sorts the (small) array (smaller number first). - For n>=3 the algorithm uses the rearrange function with the pivot chosen to be the median of A[0], A[n/2], A[n-1]. write as form: void quick_sort(int* A, int n);
Please help. How to solve this on Java language by using only Dynamic Programming? Thank you. We are given a set A of integers. Check whether we can partition A into three subsets with equal sums. It is important to note that all elements should be included in the equally divided subsets; no element should be left out, and none of the elements should be repeated in the subsets.For example: A={4,7,6,2,10,7,10,2} has such a partition: {4,2,10}, {7,7,2},{6,10}Input: A set, A, of integersOutput: if we can partition A into three subsets with equal sums, print subsets otherwise present a suitable message.
Given the following function, what happens if a[] contains just one element that doesn't match val? int binarySearch(int a[], int first, int last, int val){ if (first > last) return -1; int middle = (first + last) / 2; if (a[middle] == val) return middle; if (a[middle] < val) return binarySearch(a, middle+1, last, val); else return binarySearch(a, first, middle-1, val);} Group of answer choices binarySearch never calls itself again and terminates (recursion never happens) binarySearch calls itself once then terminates (recursion happens once) binarySearch calls itself twice then terminates (recursion happens twice) binarySearch calls itself 3 times then terminates (recursion happens 3 times)
Using recursion, write a Python function def before(k,A) which takes an integer k and an array A of integers as inputs and returns a new array consisting of all the integers in A which come before the last occurrence of k in A, in the same order they are in A. For example, if A is [1,2,3,6,7,2,3,4] then before(3,A) will return [1,2,3,6,7,2]. If k does not occur in A, the function should return None.
java ARRAY[] = [50, 11, 33, 21, 40, 50, 40, 40, 21] ARRAY[] = [11, 21, 33, 40, 50] ATTN : Further, please be reminded that you cannot use library functions to either sort and or perform the de-duplication operation. solve the problem in two ways (1) Implement the function in such a way that your solution solves the problem with O(n log2(n)) time complexity overall and O(n) space complexity. Here, n is the length of the list of input integers (array). I believe the sorting routine that can be used here is Merge Sort. Please state as code comment which sorting routine you are using, sort the arrray with that algorithm and solve the de-duplication problem thereafter. De-duplication part of the solution in itself must adhere to O(n) time and O(1) space bounds. we will not use any memory used by recursion. Important: Take the size of the input array from the User.Prompt user to input the integers in the array.PLEASE MAKE SURE TO EXPLAIN THE SORTING ALGORITHM AND DE-DUPLICATION…