& Given(1) clearly from thegivenbode. plot:30 dB.□ Resonant peak =(Mr)⇒ Resonant freq(2) Gain.7 frequency=10 dBhow do youknow gain =111120:(3) G(8) =We know the10r =(Wr)crossatfromd→ 19 (0)1 =→G(8) =G (1) =IDRough sketel.Э Ян ов20 log (Gain) = 20log |100 selfsee.= 0.юде=Phase Margin = 180+ (Phase) atсоде180+ (-180)(from bode.1plotPhase al2kwn²{=0.15.28² + 2qwnse wn²10wn√1-2(015)2=Gain(from bode plot.)WeKnowthatPhase Malgin =Bocle plot.119/= 20 10g|G|V10 rade.wn √1-2² =>oveswhich0.Phase 190Vigofrequencyqainat 1-0202кип0 + 0 + wn2161 = 10₂10.9= 10 ->R=10210 x 10.2338² + 2x 0:15 X 10.2338 + 10-23321047 143S2 +3.07s + 101.714180W = 100 is- 180°)10.233Wradfse..

Brief description: In the above given question we need to justify how the value of gain is taken as…

IMLAR 20 (1) clearly from the 10 given bode. plot: Phase 190 □ Resonant peak = 30dB. ⇒ Resmant freq Lige 10 o rade. (Wr) Rough sketel. (2) Gain. cross-oves frequency. at which Gain. денов 20 log (Gain) = 20log/ = 0. ge = 100 selfsee. Phase Margin = 180+ (Phase) at соде 180+ (-180) (from bode. plot 1 Phase al 2 kwn² W = 100 is {=0.15 8² + 2qwnse wn' -180°) 10 T wn 10.233 √1-2 (0-15)² 10- R=10 10 x 10.233² 8² + 2x 0.15 x 10.2338 + 10-2332 1047.143 S2 + 3.07s + 101.714 Q Given 7 frequency -1 0dB how do you know gain =1 (3) G(8) = We know the 10r = Gain (from bode plat) We know that Phase Malgin = → | wn √1-2² => from → 19 (0)1 = -> G(8)= 6(1) = Bocle plot. 119/= 20 10g/G/ at 1-0 1 20 kwn² 2 0+o+wn² 161= = 10 = 109 180 W radfse.

IMLAR 20 (1) clearly from the 10 given bode. plot: Phase 190 □ Resonant peak = 30dB. ⇒ Resmant freq Lige 10 o rade. (Wr) Rough sketel. (2) Gain. cross-oves frequency. at which Gain. денов 20 log (Gain) = 20log/ = 0. ge = 100 selfsee. Phase Margin = 180+ (Phase) at соде 180+ (-180) (from bode. plot 1 Phase al 2 kwn² W = 100 is {=0.15 8² + 2qwnse wn' -180°) 10 T wn 10.233 √1-2 (0-15)² 10- R=10 10 x 10.233² 8² + 2x 0.15 x 10.2338 + 10-2332 1047.143 S2 + 3.07s + 101.714 Q Given 7 frequency -1 0dB how do you know gain =1 (3) G(8) = We know the 10r = Gain (from bode plat) We know that Phase Malgin = → | wn √1-2² => from → 19 (0)1 = -> G(8)= 6(1) = Bocle plot. 119/= 20 10g/G/ at 1-0 1 20 kwn² 2 0+o+wn² 161= = 10 = 109 180 W radfse.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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