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- Task 2: Implement the function Searchingstrings that allow to search a sub-string in a given string and display the: First occurrence, Last occurrence, First occurrence from a given index and Last occurrence from a given index. You can use the following String methods: string. IndexOf(searchvalue, start) return the position of the first occurrence of specified character(s) in a string. string.lastIndexOf(searchvalue, start) return the position of the last occurrence of specified character(s) in a string. You can use the following string to test your solution: var letters = "abcdefghijklmnopqrstuvwxyzabcdefghijklm"; Write the code in a separate.js and separate.html file.Please answer it in Python write a function word_vers_dictionary(word), which takes a word (string) and returns the corresponding dictionary. For example: >>>word_vers_dictionary("tasses ") #return => {'a': 1, 's': 3, 'e': 1, 't': 1} Using the mot_vers_dictionnaire function, write a function is_anagramme(letters, word) that sends True if the string letters is an anagram of the word word, False otherwise. . For example : >>> is_anagramme("tusla", "hi") True >>> is_anagramme("salus", "salut") FalseThe goal is to rewrite the function, below, such that passes in a different list of parameters, particularly eliminating the need to pass low and high for each recursive call to binary_search. defbinary_search(nums,low,high,item): mid=(low+high)//2iflow>high:returnFalse #The item doesn't exist in the list!elifnums[mid]==item:returnTrue# The item exists in the list!elifitem<nums[mid]:returnbinary_search(nums,low,mid-1,item)else:returnbinary_search(nums,mid+1,high,item) The new function should be prototyped below. The number of changes between the given version, and the one requested is not significant. defbinary_search(nums,item):pass# Remove this and fill in with your code Tip: If you consider that high and low are used to create a smaller version of our problem to be processed recursively, the version requested will do the same thing, just through a different, more Pythonic technique.
- Using just the at, length, and substr string methods and the + (concatenate) operator, write a function that accepts a string s, a start position p, and a length l, and returns a subset of s with the characters starting at position p for a length of l removed. Don’t forget that strings start at position 0. Thus (“abcdefghijk”, 2, 4) returns “abghijk”Task 2 Get Binary 1: Implement the get_bin_1 function as directed in the comment above the function. If the directions are unclear, run the code, and look at the expected answer for a few inputs. In order to be able to compare your solution to the answer, you cannot simply print out the binary directly to the console. Instead, you have been provided with a very rudimentary stringbuilder implementation that allows you to build a string one character at a time, without the ability to erase. There are comments at the top of the code explaining how to use the stringbuilder, however you could also see how it is being used in task_2_check. Note: if you create a stringbuilder and append ‘a’, ‘b’, then ‘c’, the resulting string will be “abc” when printed. You are free to read through the stringbuilder implementation, but it is quite complicated in order to make it easy to use. As specified in the comment, you may not use division (/) or mod (%) to implement this function (as the check…Write a program that gets a list of integers from input, and outputs the integers in ascending order (lowest to highest). The first integer indicates how many numbers are in the list. Assume that the list will always contain less than 20 integers. Ex: If the input is: 5 10 4 39 12 2 the output is: 2 4 10 12 39 For coding simplicity, follow every output value by a space, including the last one. Your program must define and call the following function. When the SortVector function is complete, the vector passed in as the parameter should be sorted.void SortVector(vector<int>& myVec) #include <iostream>#include <vector>using namespace std; /* Define your function here */ int main() {/* Type your code here */ return 0;} Please help me with this problem using c++.
- Write a program that gets a list of integers from input, and outputs the integers in ascending order (lowest to highest). The first integer indicates how many numbers are in the list. Assume that the list will always contain less than 20 integers. Ex: If the input is: 5 10 4 39 12 2 the output is: 2 4 10 12 39 For coding simplicity, follow every output value by a space, including the last one. Your program must define and call the following function. When the SortVector function is complete, the vector passed in as the parameter should be sorted.void SortVector(vector<int>& myVec) Hint: There are many ways to sort a vector. You are welcome to look up and use any existing algorithm. Some believe the simplest to code is bubble sort: https://en.wikipedia.org/wiki/Bubble_sort. But you are welcome to try others: https://en.wikipedia.org/wiki/Sorting_algorithm. #include <iostream>#include <vector>using namespace std; /* Define your function here */ int main() { /*…Implement the fix_capitalization() function. fix_capitalization() has a string parameter and returns an updated string, where lowercase letters at the beginning of sentences are replaced with uppercase letters. fix_capitalization() also returns the number of letters that have been capitalized. Call fix_capitalization() in the print_menu() function, and then output the edited string followed by the number of letters capitalized. Hint 1: Look up and use Python functions .islower() and .upper() to complete this task. Hint 2: Create an empty string and use string concatenation to make edits to the string. Ex: Number of letters capitalized: 2Write the code for the following function."""def unmask_chars(s1: str, s2: str, mask: str) -> str:'''Return a new string where the character at index i iss1[i] if mask[i] is 0and s2[i] if mask[i] is 1.len(s1), len(s2), and len(mask) are equal.>>> unmask_chars('cat', 'bat', '001')'cat'>>> unmask_chars('a', 'b', '0')'a'>>> unmask_chars('apple', 'graph', '01011')'arpph''''# TODO: Write your code here
- Write a program to reverse the words of a string. Implement a function reverse () that reverses the string between indexes i and j inclusively. Prototype of the function is given below. void reverse (char *str, int i, int j)Improve the given code below, make sure that the code will require input from the user. Problem: Write a JavaScript function that would accept a string and return the reverse of that string. const reverse = (str) => {const arr = []; //stores character in rev orderconst len = str.length; //finds the length of the stringlet i;for(i = len; i >= 0; i--)arr.push(str[i]); //adds the chars of str to arrreturn arr.join('');} let stringTest, reverseString; //for dummy stringstringTest = "john gabriel";reverseString = reverse(stringTest); console.log("Num3");console.log(`Reverse of the string "${stringTest}" is: "${reverseString}"`);console.log("\n");Implement regular expression matching with support for '.' and '*'. '.' Matches any single character.'*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype should be:bool is_match(const char *s, const char *p) Some examples:is_match("aa","a") → falseis_match("aa","aa") → trueis_match("aaa","aa") → falseis_match("aa", "a*") → trueis_match("aa", ".*") → trueis_match("ab", ".*") → trueis_match("aab", "c*a*b") → true""" def is_match(str_a, str_b): """Finds if `str_a` matches `str_b` Keyword arguments: str_a -- string str_b -- string """ len_a, len_b = len(str_a) + 1, len(str_b) + 1 matches = [[False] * len_b for _ in range(len_a)] # Match empty string with empty pattern matches[0][0] = True # Match empty string with .* for i, element in enumerate(str_b[1:], 2): matches[0][i] = matches[0][i - 2] and element == '*' for i, char_a in enumerate(str_a, 1):…