Please help solve for activation energy. I made an error in my calculations and only plugged it up to the highlighted part. Please solve for the rest. In(-0.92384542/-0.00118496)=-E,/8.3145 J/mol*K (1/274 - 1/293)In 779.64= -E,/8.3145 J/mol (0.00365 - 0.00341)6.65/0.00024= -E,/8.3145 J/mol-E/8.3145 J/mol = 3822.91.a'E,= -31785.64 J/molE= -31.79 KJ/mola

The given problem is :- ln(-0.92384542/-0.00118496) = -Ea/8.3145 J/molK(1/274 - 1/293)

In(-0.92384542/-0.00118496)=-E,/8.3145 J/mol*K (1/274 - 1/293) In 779.64= -E/8.3145 J/mol (0.00365 - 0.00341) 6.65/0.00024= -E/8.3145 J/mol -E/8.3145 J/mol = 3822.91 . %3D E= -31785.64 J/mol E,= -31.79 KJ/mol

In(-0.92384542/-0.00118496)=-E,/8.3145 J/mol*K (1/274 - 1/293) In 779.64= -E/8.3145 J/mol (0.00365 - 0.00341) 6.65/0.00024= -E/8.3145 J/mol -E/8.3145 J/mol = 3822.91 . %3D E= -31785.64 J/mol E,= -31.79 KJ/mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter17: Spontaneity, Entropy, And Free Energy

Section: Chapter Questions

Problem 2ALQ: For a liquid, which would you expect to be larger, Sfusion or Sevaporation? Why?

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Question

Please help solve for activation energy. I made an error in my calculations and only plugged it up to the highlighted part. Please solve for the rest.

In(-0.92384542/-0.00118496)=-E,/8.3145 J/mol*K (1/274 - 1/293)
In 779.64= -E,/8.3145 J/mol (0.00365 - 0.00341)
6.65/0.00024= -E,/8.3145 J/mol
-E/8.3145 J/mol = 3822.91.
a'
E,= -31785.64 J/mol
E= -31.79 KJ/mol
a

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