Question

Asked Dec 1, 2019

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In a certain year, 88% of all Caucasians in the U.S., 77% of all African-Americans, 77% of all Hispanics, and 74% of residents not classified into one of these groups used the Internet for e-mail. At that time, the U.S. population was 68% Caucasian, 10% African-American, and 10% Hispanic. What percentage of U.S. residents who used the Internet for e-mail were Hispanic? (Round your answer to the nearest whole percent.)

Step 1

Let *A* be the event of Caucasians, *B* be the event of sleeting African-Americans, *C* be the event of selecting Hispanics and *D* be the event of other in the US that used the internet for email.

Hence the probability of selecting any group is equally likely and mutually exclusive.

That is, *P* (*A*) = 0.88, *P*(*B*) = 0.77 , *P*(*C*) = 0.77 and *P*(*D*) = 0.74.

It is given that the U.S population Caucasian has 68%, U.S population has African-American has 10% , U.S population Hispanic has 10% and The percentage of American not classified into any of this group is (1– 0.68 – 0.10 – 0.10)*100 = 12%

Let *S* be the event that the selected U.S residents that used internet, then the priory probability are,

*P(S|A)= 0.68, P(S|B) = 0.10, P(S|C) = 0.10 *and* P(S|D) = 0.12*

The percentage of U.S residents that used internet is

Step 2

The proportion of U.S residents who used the ...

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