In a random sample of 6 cell phones, the mean full retail price was $502.30 and the standard deviation was $183.00. Further research suggests that the populationmean is $434.59. Does the t-value for the original sample fall between to 95 and to 95? ASsume that the population of full retail prices for cell phones is normallySoldistributed.fall between -to.95 and to.95 because to.95 .The t-value of t(Round to two decimal places as needed.)Questiontions left this cyenews on 11/24/ter QAll QPendAnswORejecSubjects?Math Enter your answer in each of the answer boxes.wXPtvNOV209國目11MacBook ProDDDIIF11F10F9F8F7000F6F5F4F3F2F1

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Asked Nov 11, 2019
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In a random sample of 6 cell phones, the mean full retail price was $502.30 and the standard deviation was $183.00. Further research suggests that the population
mean is $434.59. Does the t-value for the original sample fall between to 95 and to 95? ASsume that the population of full retail prices for cell phones is normally
Sol
distributed.
fall between -to.95 and to.95 because to.95 .
The t-value of t
(Round to two decimal places as needed.)
Question
tions left this cy
enews on 11/24/
ter Q
All Q
Pend
Answ
ORejec
Subjects
?
Math Enter your answer in each of the answer boxes.
wXP
tv
NOV
209國目
11
MacBook Pro
DD
DII
F11
F10
F9
F8
F7
000
F6
F5
F4
F3
F2
F1
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In a random sample of 6 cell phones, the mean full retail price was $502.30 and the standard deviation was $183.00. Further research suggests that the population mean is $434.59. Does the t-value for the original sample fall between to 95 and to 95? ASsume that the population of full retail prices for cell phones is normally Sol distributed. fall between -to.95 and to.95 because to.95 . The t-value of t (Round to two decimal places as needed.) Question tions left this cy enews on 11/24/ ter Q All Q Pend Answ ORejec Subjects ? Math Enter your answer in each of the answer boxes. wXP tv NOV 209國目 11 MacBook Pro DD DII F11 F10 F9 F8 F7 000 F6 F5 F4 F3 F2 F1

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Expert Answer

Step 1

Given information:

Sample size (n) = 6

Sample mean = $502.30

Standard deviation = $183.00

Step 2

Confidence level = 95%

Significance level = 1- Confidence level

                              =1-95%

                              =1-0.95

                              =0.05

Degree of freedom =n-1

                               =6-1

                               =5

Step 3

The value of t-critical in two tail test at 0.05 signi...

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