In a sample of 30 participants, a researcher estimates the 95% CI for a sample with a mean of Μ1-Μ2 = 0.7 and an estimated standard error for the difference sΜ1-Μ2 of 0.2. What is the confidence interval at this level of confidence?
In a sample of 30 participants, a researcher estimates the 95% CI for a sample with a mean of Μ1-Μ2 = 0.7 and an estimated standard error for the difference sΜ1-Μ2 of 0.2. What is the confidence interval at this level of confidence?
From the given question
Sample size (n) =30, mean difference (M1-M2) =0.7 and standard error difference (SM1-M2) =0.2.
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MD 0.7, SMD-0.2 and n=30
Formula for confidence interval (CI) is
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CI=MD(txSMD) >(1) Here, t-value is for 95% confidence level and sample size 30 a 1-0.95 =0.025 and degree of freedom (df)=n-1=30-1=29 2 t-value for 2 from the t-distribution table,t 2.045 (0.025,29)
Let substitute these values in equation...
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CI-MD (txSMD) 0.7+(2.045x0.2 (0.291, 1.109)
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Statistics
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