In a survey of women in a certain country (ages 20 - 29), the mean height was 62.8 inches with a standard deviation of 2.91 inches. A swer the following questions about the specified normal distribution. (a) What height represents the 95th percentile? (b) What height represents the first quartile? Click to view page 1 of the table. Click to view page 2 of the table. (a) The height that represents the 95th percentile is (Round to two decimal places as needed.) inches. Check Adswer Clear All Get More Help- View an Example Help Me Solve This

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Q: In a survey of women in a certain country (ages 20 - 29), the mean height was 65.1 inches with a…

A: We have In a survey of women in a certain country (ages 20 - 29), the mean height was 65.1 inches…

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A: Given Information:  Mean height = 62.6 inches  Standard Deviation = 2.66

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A: Given, mean height= 66.8 inches standard deviation=2.72 inches Then the first Quartile (Q1)…

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A: Solution: Let X be the height. From the given information, X follows normal distribution with mean…

Q: In a survey of women in a certain country (ages 20 - 29), the mean height was 62.9 inches with a…

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Q: In a survey of women in a certain country​ (ages20−​29),the mean height was 66.7 inches with a…

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A: The quartile is a term used in statistics that divides the statistical observation into 4 divisions.…

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 66.9 inches with a…

A:

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A: GivenMean(μ)=65.2standard deviation(σ)=2.84

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A: Let "X" be the mean height of women in a certain country (ages 20-29) in inches.

Q: In a survey of women in a certain country (ages 20 - 29), the mean height was 62.6 inches with (a)…

A:

Q: In a survey of women in a certain country (ages 20 - 29), the mean height was 66.8 inches with a…

A: (a) Obtain the height that represents the 95th percentile. The height that represents the 95th…

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Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 64.1 inches with a…

A: GivenMean(μ)=64.1standard deviation(σ)=2.84

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 65.4 inches with a…

A: Given that, μ=65.4 inches and σ=2.78 inches (a) The height represents the 95th ​percentile is,…

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A: GivenMean = 63.4 inchesStandard deviation = 2.87 inches The Z score for 95th percentile is 1.645

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A: a) The Z-score of a random variable X is defined as follows: Z = (X – µ)/σ. Here, µ and σ are the…

Q: survey of women in a certain country​ (ages 20−​29), the mean height was 66.4 inches with a standard…

A:

Q: In a survey of women in a certain country (ages 20 - 29), the mean height was 62 9 inches with a…

A: Given Data : Population Mean,μ = 62.9 Population Standard Deviation,σ = 2.71

Q: (a) What height represents the 95th ​percentile? ​(b) What height represents the first​ quartile?

A: (a) The random variable X is defined as the height of women which follows normal distribution with…

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A: It is given that the mean height is 62.9 inches and standard deviation is 2.66 inches.

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Q: Grades in an exam are normally distributed with a mean of 60 and a standard deviation of 10. What is…

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Q: a survey of women in a certain country​ (ages 20−​29), the mean height was 63.5 inches with a…

A:

Q: In a survey of women in a certain country (ages 20 - 29), the mean height was 63.2 inches with a…

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Q: On a standard normal distribution, what percentage of scores lie within 1.49 standard deviations on…

A: For standard normal distributionMean(μ)=0sd(σ)=1P(-1.49<z<1.49)=?

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Q: In a survey of women in a certain country (ages 20-29), the mean height was 65.6 inches with a…

A: (a)The height represents the 95th percentile is 70.32, which is obtained by using the Excel function…

Q: In a survey of women in a certain country​ (ages 20−​29), the mean height was 66.8 inches with a…

A: (a) Obtain the height that represents the 95th percentile. The height that represents the 95th…

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A: Given data, μ=60σ=16n=75 standard deviation for the sample mean(σx)=?

Q: In a survey of women in a certain country (ages 20 - 29), the mean height was 63.3 inches with a…

A: GivenMean = 63.3 inchesStandard deviation = 2.84 inches The Z score for 95th percentile is 1.645 The…

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A: Given that, (a) The height that represents the 95th percentile is, Thus, the height that…

Q: In a survey of women in a certain country (ages 20-29), the mean height was 63.6 inches with a…

A: GivenMean(μ)=63.6standard deviation(σ)=2.75

Q: What height represents the 95th ​percentile? ​(b) What height represents the first​ quartile?

A: Here Given  For survey of women in certain country for their height Mean=μ=66.6 Inches SD=σ=2.72…

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A: Given that, μ=66.1 inchesσ=2.74 inches (a) The height represents the 95th percentile is,

Q: In a survey of women in a certain country (ages 20 - 29), the mean height was 62.5 inches with a…

A: Givenμ=62σ=2.68