In a TV show, there are three boxes. Red, Green, and Yellow. One of the boxes has a frog in it and the other 2 is empty. You are trying to avoid to open the box with the frog. Assume that you randomly selected a box, let’s say Green. The game host opens one of the unselected box, say Red, and showed there was no frog in it. The host knows which one includes the frog. Now the host proposes you the option of either staying at the box that you have chosen or change it to the remaining box, (Yellow in this case). What is the probability of finding the frog if you change your selection and if you don't change? Compare the results and make the decision about switching your initial selection. (I think the exact opposite monty hall problem)
In a TV show, there are three boxes. Red, Green, and Yellow. One of the boxes has a
frog in it and the other 2 is empty. You are trying to avoid to open the box with the frog.
Assume that you randomly selected a box, let’s say Green. The game host opens one of
the unselected box, say Red, and showed there was no frog in it. The host knows which
one includes the frog. Now the host proposes you the option of either staying at the box
that you have chosen or change it to the remaining box, (Yellow in this case). What is the
probability of finding the frog if you change your selection and if you don't change?
Compare the results and make the decision about switching your initial selection.
(I think the exact opposite monty hall problem)
Step by step
Solved in 2 steps
