In a two peg test of a dumpy level using alternative method, the following observations were taken. Point M is equidistant from both A and B, while P is 2.50 m away from A along the extension of line AB and 79.27 from B. Rod reading at point A Rod reading at point B m 3 Instrument set-up at M 0.296 m 0.910 m Instrument set-up at P 1.563 m 2.140 m a) Determine the true difference in elevation between A and B b) Determine the error in the rod reading at B with instrument still at P

In a two peg test of a dumpy level using alternative method, the following observations were taken. Point M is equidistant from both A and B, while P is 2.50 m away from A along the extension of line AB and 79.27 from B. Rod reading at point A Rod reading at point B m 3 Instrument set-up at M 0.296 m 0.910 m Instrument set-up at P 1.563 m 2.140 m a) Determine the true difference in elevation between A and B b) Determine the error in the rod reading at B with instrument still at P

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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In the two-peg test of a dummy level, the following observations are taken. On point A On point B INSTRUMENT SET UP at M 2.682 1.239 INSTRUMENT SET UP at P 1.876 0.565 Point M is equidistance from both A and B with 92 meters, while P is 2.50m away from A along the extension of line AB. Requirements: Determine the true difference in elevation between point A and B. With the level still set up at P, determine the rod reading on A and B to which the line of sight should be adjusted. If the instrument needs to be adjusted, determine the following false difference in elevation inclination of the line of sight and the error in the reading of far rod A and B instrument set up at P.
SURVEYING Given the following differential level notes: STA BS FS BM1 1.73 - TP1 2.5 3.8 TP2 2.75 1.7 BM2 3.15 3.32 TP3 2.45 3.22 TP4 3.9 2.5 TP5 2.78 3.02 BM3 - 1.77 Base on the differential leveling of note in the previous problem, if the elevation of TP3 = 267.28 m, determine the elevation of BM1
Q#1: A profile levelling is carried out and consecutive readings were observed on staff rod along a chain line at common interval of 10 meter which are listed below in table. First reading is taken on bench mark of 105.615 meter reduce level. Station Points Chainage (m) Staff Readings (m) Remarks BS IS FS 1 00 3.005 BM 2 10 2.285 3 20 1.560 4 30 1.785 5 40 2.105 6 50 2.875 3.105 CP 1 X 53.35 3.465 7 60 3.955 8 70 3.120 9 80 3.015 10 90 2.580 11 100 1.955 CP 2 Determine the reduce levels of all points using both line of collimation and rise and fall method. (Present your answer in table form).
Solve by Rise and fall method Ques- The following consecutive readings were taken with dumpy level and 4 m levelling staff on continuously sloping ground at a common interval of 30 m. 0.585 on A, 0.936, 1.953, 2.846, 3.644, 3.938, 0.962, 1.035, 1.689, 2.534, 3.844, 0.956, 1.579, 3.016 on B. The elevation of A was 520.450 m. (a) Enter the readings in level book. (b) Calculate R.L. of all the points by rise - fall method. (c) Apply usual arithmetical checks. (d) Determine the gradient of line AB.
The following consecutive readings were taken with a level and a 4mt. leveling staff on acontinuously sloping ground at common intervals of 30 m:0.855(onA),1.545,2.335,3.115,3.825,0.455,1.380,2.055,2.855,3.455,0.585,1.015,1.850,2.755,3.845(on B)Enter the readings on a level field book and work out the staff readings on that, Find theR.L of different points using Collimation Plane Method. RL of the BM is 200.000m.Calculate the slope of the ground.
In a two-peg test for a dumpy level, the following observations were taken: With the level set-up at X (midway between A and B), the rod reading taken at A and B are 1.155m and 1.77m, respectively. With the level positioned at Y, the rod readings at A and B are recorded as 2.423m and 2.999m, respectively. Point Y is located 1.67m from A along the extension of line AB and 76.91m from B. Determine the correct reading on the near rod for a horizontal line of sight.
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HELP ASAP!!! a = 5.4 m , b= 3.8 m, c= 1.9 m