PLEASE SOLVE THIS AS SOON AS POSSIBLE AND SURELY I WILL RATE YOU. THANK YOU ( STEP BY STEP PROCESS) Situation #1The compound beam is pin supported at C and supported by a roller at Aand B. There is a hinge (pin) at D. Determine the reactions at thesupports. Neglect the thickness of the beam.Ak4 k30%A(100+Bft+D4 ft 2 ft15 k.ftBASO000Yk4DempseC ft 8 ft Aft-1. What is the vertical reaction at A? (k)2. What is the vertical reaction at B? (k)3. What is the vertical reaction at C? (k)4. What is the horizontal reaction at C? (k)5. What is the moment at point A? (k-ft)6. What is the moment at point D? (k-ft)7. What is the moment at a point A ft left of point C? (k-ft)8. What is the shear at a point (A + 4) ft left of point C? (k)9. What is the shear at a point (A + 8 + C/2) ft left of point C? (k)10. What is the moment at point C? (k-ft)2 of 8Given:X=157Y= 48A=9B=5C=4

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Answered: The compound beam is pin supported at C…

The compound beam is pin supported at C and supported by a roller at A and B. There is a hinge (pin) at D. Determine the reactions at the supports. Neglect the thickness of the beam.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.

Question

PLEASE SOLVE THIS AS SOON AS POSSIBLE AND SURELY I WILL RATE YOU. THANK YOU ( STEP BY STEP PROCESS)

Situation #1
The compound beam is pin supported at C and supported by a roller at A
and B. There is a hinge (pin) at D. Determine the reactions at the
supports. Neglect the thickness of the beam.
Ak
4 k
30%
A
(100+
Bft+
D
4 ft 2 ft
15 k.ft
BA
SO
000
Yk
4
Dempse
C ft 8 ft Aft-
1. What is the vertical reaction at A? (k)
2. What is the vertical reaction at B? (k)
3. What is the vertical reaction at C? (k)
4. What is the horizontal reaction at C? (k)
5. What is the moment at point A? (k-ft)
6. What is the moment at point D? (k-ft)
7. What is the moment at a point A ft left of point C? (k-ft)
8. What is the shear at a point (A + 4) ft left of point C? (k)
9. What is the shear at a point (A + 8 + C/2) ft left of point C? (k)
10. What is the moment at point C? (k-ft)
2 of 8
Given:
X=157
Y= 48
A=9
B=5
C=4

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