In an array A, every integer from O to n is present with the exception of one. We are unable to access a full integer in A in this case with a single operation. The sole operation we can use to access the elements of A, which are represented in binary, is "get the jth bit of A[i]," which has a constant time cost. To discover the missing integer, write some code. Do you have O(n) time?

In an array A, every integer from O to n is present with the exception of one. We are unable to access a full integer in A in this case with a single operation. The sole operation we can use to access the elements of A, which are represented in binary, is "get the jth bit of A[i]," which has a constant time cost. To discover the missing integer, write some code. Do you have O(n) time?

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter8: Arrays And Strings

Section: Chapter Questions

Problem 24PE

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An array A contains all the integers from O to n, except for one number whichis missing. In this problem, we cannot access an entire integer in A with a single operation. Theelements of A are represented in binary, and the only operation we can use to access them is "fetchthe jth bit of A[i];' which takes constant time. Write code to find the missing integer. Can you do itin O(n) time?
Alex had an array A of length N such that 1≤Ai≤N for all 1≤i≤N. He constructed another binary array B of length N in the following manner: Bi=1 if the frequency of element i in A is odd. Bi=0 if the frequency of element i in A is even. Such an array B is called the parity encoding array of A. For example, if A=[1,1,2,3], then B=[0,1,1,0]. Unfortunately, he completely forgot the array A and vaguely remembers the parity encoding array B. He is now wondering whether there exists any valid array A for which the parity encoding array is B. Can you help himf? Input Format The first line contains a single integer T — the number of test cases. Then the test cases follow. The first line of each test case contains an integer N — the size of the arrays A and B. The second line of each test case contains N space-separated integers B1,B2,…,BN denoting the parity encoding array B. Output Format For each test case, output YES if there exists any valid array A for which the parity encoding…
Except for one number, an array A includes all the integers from O to n. We cannot access a full integer in A with a single operation in this scenario. The elements of A are encoded in binary, and the sole way to access them is to "get the jth bit of A[i];" this operation takes constant time. Create code to locate the missing integer. Can you do it in O(n) time?
1) Consider an integer array a of length n with indexing starting at 0, where n is a positive integer.If the elements of array a are to be written out in reverse order, which of the following C++ code fragment does NOT do the job? Question options: a. int i=n-1; while (i>=1){cout << a[i] << endl; i = i-1;} cout << a[i] << endl; b. int i=n-1; while (i>=1){cout << a[i] << endl; i = i-1;} c. int i=n-1; while (i>=0){cout << a[i] << endl; i = i-1;} d. int i=n; while (i>0){cout << a[i-1] << endl; i = i-1;} 2) Assume we use 8-bit cell to store floating point numbers, 1 bit for sign, 3 bits for excessed exponent, and 4 bits for significand. What is the decimal value for a cell with bit pattern 0 111 1101 Question options: a. 125 b. 224…
Given two arrays A and B of equal size N, the task is to find if given arrays are equal or not. Two arrays are said to be equal if both of them contain same set of elements, arrangements (or permutation) of elements may be different though.Note : If there are repetitions, then counts of repeated elements must also be same for two array to be equal. Example 1: Input: N = 5 A[] = {1,2,5,4,0} B[] = {2,4,5,0,1} Output: 1.
Given an array A = [10, 7, 4, 2, 1], and target = 7, return the index of the target if found, else return -1. 1. Can this problem be solved in O(logN)? 2. If so, write the implementation. Mention time and space complexity 3. If this problem cannot be solved using O(logN), what is the solution that you suggest - write the code and also mention time and space complexity.
.Here an array of integers nums sorted in ascending order, find the startingand ending position of a given target value. If the target is not found in thearray, return [-1, -1]. For example:Input: nums = [5,7,7,8,8,8,10], target = 8Output: [3,5]Input: nums = [5,7,7,8,8,8,10], target = 11Output: [-1,-1].
Consider an array A of N values (N entered by the user). Write a C program that creates a second array B such that the i-th element of B, i.e., B[i] is equal to A[0] *A[1] * A[2] * ... A[i]; In other words:- B[0] = A[0]- B[1] = A[0] * A[1];- B[2] = A[0] * A[1] * A[2];- B[3] = A[0] * A[1] * A[2] * A[3]- ....etc.For this exercise, we would like to implement two solutions and compare their complexity /performance in terms of computation time.Solution 1: Implement blindly the following algorithms: for each element B[i], compute A[0] *A[1] * A[2] * .... *A[i] and save the result in B[i];To test the solution, create an array A of 1000 elements and initialize each of its elements with arandom value (instead of asking the user to . To do that, use the function rand, which, every timecalled, returns a random number Questions:- How long does your program take to produce the solution?- Analyze the solution above and explain why it is taking long time. What are the mainfactors that affect how long…
Given an integer n and an array a of length n, your task is to apply the following mutation to a: Array a mutates into a new array b of length n. For each i from 0 to n - 1, b[i] = a[i - 1] + a[i] + a[i + 1]. If some element in the sum a[i - 1] + a[i] + a[i + 1] does not exist, it should be set to 0. For example, b[0] should be equal to 0 + a[0] + a[1].
Modify the Partition function so that after running it, any input array A is partitioned into three parts: the left part consisting of all elements < pivot, the middle part consisting of all elements = pivot, and the right part consisting of the rest Write down the pseudo-code for this modified version of the Partition function. (must be an in-place algorithm with Θ(n) time complexity.) Hint: Define three indices: i as the end of the left part, k as the end of the middle part, and j denoting the current index which is used in the for-loop.
The drawback of this approach, is that with each recursive function call, we only reduce the size of the array by one element, and we use a storage space for one activation record. A faster approach is, with each recursive call, reduce the size of the array by 3 elements. a. Write a reduce-and-conquer recursive function FastRecSum()(C++ or python) that find the sum of all float (real) elements in an array of size n. b. Using addition of float (real) values as a basic operation, set up and solve a recurrence relationship to compute the complexity of your code, as a function of the size n of the array.
Find the complexity of the function used to find the kth smallest integer in an unordered array of integers: int selectkth(int a[], int k, int n) {int i, j, mini, tmp; for (i = 0; i < k; i++) { mini = i; for (j = i+1; j < n; j++) if (a[j]<a[mini]) mini = j; tmp = a[i]; a[i] = a[mini]; a[mini] = tmp; }return a[k-1];}