In an earlier step, an FBD was created for the bottom-most block under the assumption of equilibrium. Which statement best describes the modifications necessary if that FBD is redrawn under the assumption ay<0? The weight vector labeled F g,1 would be unchanged. The normal-force vector labeled Fn,f→1 would become shorter, but the normal-force vector labeled Fn,2→1 would become shorter by a greater amount. The weight vector labeled F g,1 would change length, becoming shorter, but the normal-force vectors would be unchanged. The diagram requires no changes because all of the forces remain the same. The weight vector labeled Fg,1 and the normal-force vector labeled Fn,2→1 would be unchanged, but the normal-force vector labeled Fn,f→1 would become shorter. Because things feel partially weightless in the elevator, all three vectors would be shorter. The weight vector labeled Fg,1 would be unchanged. The normal-force vector labeled Fn,2→1 would become longer, but the normal-force vector labeled Fn,f→1 would become shorter. The weight vector labeled Fg,1 would be unchanged. The normal-force vector labeled Fn,2→1 would become shorter, but the normal-force vector labeled Fn,f→1 would become shorter by a greater amount.
In an earlier step, an FBD was created for the bottom-most block under the assumption of equilibrium. Which statement best describes the modifications necessary if that FBD is redrawn under the assumption ay<0? The weight vector labeled F g,1 would be unchanged. The normal-force vector labeled Fn,f→1 would become shorter, but the normal-force vector labeled Fn,2→1 would become shorter by a greater amount. The weight vector labeled F g,1 would change length, becoming shorter, but the normal-force vectors would be unchanged. The diagram requires no changes because all of the forces remain the same. The weight vector labeled Fg,1 and the normal-force vector labeled Fn,2→1 would be unchanged, but the normal-force vector labeled Fn,f→1 would become shorter. Because things feel partially weightless in the elevator, all three vectors would be shorter. The weight vector labeled Fg,1 would be unchanged. The normal-force vector labeled Fn,2→1 would become longer, but the normal-force vector labeled Fn,f→1 would become shorter. The weight vector labeled Fg,1 would be unchanged. The normal-force vector labeled Fn,2→1 would become shorter, but the normal-force vector labeled Fn,f→1 would become shorter by a greater amount.
Chapter10: Origin Of The Solar System And Extrasolar Planets
Section: Chapter Questions
Problem 22RQ
Related questions
Question
In an earlier step, an FBD was created for the bottom-most block under the assumption of equilibrium. Which statement best describes the modifications necessary if that FBD is redrawn under the assumption ay<0?
| The weight vector labeled F g,1 would be unchanged. The normal-force vector labeled Fn,f→1 would become shorter, but the normal-force vector labeled Fn,2→1 would become shorter by a greater amount. |
| The weight vector labeled F g,1 would change length, becoming shorter, but the normal-force vectors would be unchanged. |
| The diagram requires no changes because all of the forces remain the same. |
| The weight vector labeled Fg,1 and the normal-force vector labeled Fn,2→1 would be unchanged, but the normal-force vector labeled Fn,f→1 would become shorter. |
| Because things feel partially weightless in the elevator, all three vectors would be shorter. |
| The weight vector labeled Fg,1 would be unchanged. The normal-force vector labeled Fn,2→1 would become longer, but the normal-force vector labeled Fn,f→1 would become shorter. |
| The weight vector labeled Fg,1 would be unchanged. The normal-force vector labeled Fn,2→1 would become shorter, but the normal-force vector labeled Fn,f→1 would become shorter by a greater amount. |
Transcribed Image Text:M3
m2
m1
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Step 1: Draw the free body diagram:
VIEWStep 2: Determine the the magnitude of the force of the floor on the bottom-most block taking any a(y):
VIEWStep 3: Calculate the normal forces at equilibrium:
VIEWStep 4: Calculate the normal forces when a(y)<0:
VIEWStep 5: Find out the necessary modification:
VIEWSolution
VIEW
Trending now
This is a popular solution!
Step by step
Solved in 6 steps with 6 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Recommended textbooks for you