In ARST, s = 620 cm, r = 210 cm and ZR=17°. Find all possible values of ZS, to the nearest 1oth of a degree.

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A: Consider the given equation as tanθ=-13

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A: .

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A: See below the answer

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A: Given,  Arc length,  S=11π6 θ=Sr If we take r=1,  We get, θ=S Hence, θ=11π6radians or 330°

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A: Please refer to the image below

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Q: a

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