In concurrent programming, a "critical section" is a part of a multi-process program thata)may not be concurrently executed by more than one of the program's thread. Let us consider a 2processes solution:do {flag[i] = TRUE;while(flag[j]); %waitCRITICAL SECTIONflag[i] = FALSE;REMAINDER SECTION} while (TRUE);Pseudo-code of $P_i$ (the one of $P_j$ is symmetric)} Does the given solution sattisfy the mutual exclusion requirement? Explain (a(i) ísimple 'yes-no' answer is NOT enough. What is the mutual exclusion requirement? Why is(not?) sattisfied?)(ii)(iii)your answer (no point without a valid simluation)(iv)deadlock), how can you modify the given solution to make it working?Does the given solution sattisfy the progress requirement? ExplainDoes the given solution have the risk of deadlock? Make a simulation to supportif your answer to the previous question is positive (i.e. Yes, there is the risk of

1. Mutual exclusion property states that at any given time only one process is executing critical…

In concurrent programming, a "critical section" is a part of a multi-process program ot be concurrently executed by more than one of the program's thread. Let us consider ses solution: flag[i] = TRUE; while(flag[j]); %wait CRITICAL SECTION flag[i] = FALSE; %3! REMAINDER SECTION } while (TRUE); -code of $P_i$ (the one of $P-j$ is symmetric) } Does the given solution sattisfy the mutual exclusion requirement? Explain simple 'yes-no' answer is NOT enough. What is the mutual exclusion requirement? Wh (not?) sattisfied?) Does the given solution sattisfy the progress requirement? Explain Does the given solution have the risk of deadlock? Make a simulation to sup

In concurrent programming, a "critical section" is a part of a multi-process program ot be concurrently executed by more than one of the program's thread. Let us consider ses solution: flag[i] = TRUE; while(flag[j]); %wait CRITICAL SECTION flag[i] = FALSE; %3! REMAINDER SECTION } while (TRUE); -code of $P_i$ (the one of $P-j$ is symmetric) } Does the given solution sattisfy the mutual exclusion requirement? Explain simple 'yes-no' answer is NOT enough. What is the mutual exclusion requirement? Wh (not?) sattisfied?) Does the given solution sattisfy the progress requirement? Explain Does the given solution have the risk of deadlock? Make a simulation to sup

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Implement a solution to the critical section problem with threads using semaphores. you must add a third counting thread which counts by 1 each time it enters its critical section to 3,000,000. Each counts to 3,000,000 for a total of 9,000,000.
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Consider an ARMv8 computer that is running more than one thread of execution. The computer has certain resources that must not be accessed or modified by different threads at the same time. These resources could be peripheral devices or memory buffers and data structures that are accessible by any threads. This type of concurrency control is a general computer science problem. It is possible to protect a shared resource by implementing a lock function, which allows a thread request ownership of the resource. An unlock function is necessary to allow software to release the lock. A simple lock system could be implemented using a variable in memory that can contain one of two values, LOCKED and, UNLOCKED. The action is to first read the value from memory, and if the lock is UNLOCKED then the value can be updated to LOCKED and written back to memory. This method is vulnerable to another thread modifying the value in memory in between the first read and the write-back of the new value. The…
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Solve the producer and consumer problem with inter thread communication (join(), wait(), sleep() etc.) modifying the given C code. #include <pthread.h> #include <stdio.h> #include <string.h> #define MAX 10 //producers and consumers can produce and consume upto MAX #define BUFLEN 6 #define NUMTHREAD 2 /* number of threads */ void * consumer(int *id); void * producer(int *id); char buffer[BUFLEN]; char source[BUFLEN]; //from this array producer will store it's production into buffer int pCount = 0; int cCount = 0; int buflen; //initializing pthread mutex and condition variables pthread_mutex_t count_mutex = PTHREAD_MUTEX_INITIALIZER; pthread_cond_t nonEmpty = PTHREAD_COND_INITIALIZER; pthread_cond_t full = PTHREAD_COND_INITIALIZER; int thread_id[NUMTHREAD] = {0,1}; int i = 0; int j = 0; main(){ int i; /* define the type to be pthread */ pthread_t thread[NUMTHREAD]; strcpy(source,"abcdef"); buflen = strlen(source); /* create 2…