In Exercises 1-4, determine if the given ordered triple is a solution of the system. 1. (2, –1, 3) x + y + z = 2y – z = 4 1 y - z 2. (5, -3, -2) 2х — = -1 x + y + z = x + 2y 3z 5 3x + 4y + 2z -1 3. (4, 1, 2) 2y 2x + 3y 2 11 y – 4z = -7 4. (-1, 3, 2) х — 2z -5 y - 3z = -3 2x z = -4 IL||

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