In Fig. 1, a thin glass rod forms a semicircle of radius r= 10.00 cm. Charge is uniformly distributed along the rod, with q=20.00 mC in the upper half and q=-20.00 mC in the lower half. What are the (a) magnitude and (b) direction (relative to the positive direction of the x axis) of the electric field at P, the center of the semicircle fig.1 +g -9

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter25: Gauss’s Law
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Problem 43PQ: The nonuniform charge density of a solid insulating sphere of radius R is given by = cr2 (r R),...
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In Fig. 1, a thin glass rod forms a semicircle of radius r= 10.00 cm. Charge is uniformly
distributed along the rod, with q = 20.00 mC in the upper half and q=-20.00 mC in the lower
half. What are the (a) magnitude and (b) direction (relative to the positive direction of the x axis)
of the electric field at P, the center of the semicircle
fig.1
+q
P
-9
Transcribed Image Text:In Fig. 1, a thin glass rod forms a semicircle of radius r= 10.00 cm. Charge is uniformly distributed along the rod, with q = 20.00 mC in the upper half and q=-20.00 mC in the lower half. What are the (a) magnitude and (b) direction (relative to the positive direction of the x axis) of the electric field at P, the center of the semicircle fig.1 +q P -9
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