In order to measure the free-fall acceleration on a distant planet with no orbiting satellite, a 1.5-meter-long pendulum made of a massless lead string holding a very small 2-kg gold mass is brought to the planet's surface. The planet has a temperature of 470 °C, and once the pendulum is lifted at an angle of 15° from the vertical, it swings left and right with a period of 2.38 seconds. If the original measurement for the pendulum was taken when the temperature was 25 °C, what is the free- fall acceleration on that planet? Round to the nearest hundredth (0.01). Justify your answer using your rationale and equations used.

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
Publisher:OpenStax
Chapter1: Temperature And Heat
Section: Chapter Questions
Problem 105AP: How much stress is cleated in a steel beam if its temperature changes from 15 to 40 but it cannot...
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In order to measure the free-fall acceleration on a distant planet with no orbiting satellite, a 1.5-meter-long
pendulum made of a massless lead string holding a very small 2-kg gold mass is brought to the planet's surface.
The planet has a temperature of 470 °C, and once the pendulum is lifted at an angle of 15° from the vertical, it
swings left and right with a period of 2.38 seconds.
If the original measurement for the pendulum was taken when the temperature was 25 °C, what is the free-
fall acceleration on that planet? Round to the nearest hundredth (0.01). Justify your answer using your
rationale and equations used.
Transcribed Image Text:In order to measure the free-fall acceleration on a distant planet with no orbiting satellite, a 1.5-meter-long pendulum made of a massless lead string holding a very small 2-kg gold mass is brought to the planet's surface. The planet has a temperature of 470 °C, and once the pendulum is lifted at an angle of 15° from the vertical, it swings left and right with a period of 2.38 seconds. If the original measurement for the pendulum was taken when the temperature was 25 °C, what is the free- fall acceleration on that planet? Round to the nearest hundredth (0.01). Justify your answer using your rationale and equations used.
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