In order to protect eyes from damaging near ultraviolet light (UVA with wavlength of 397 nm), sunglasses are often coated so this light_is reflected. The index of refraction of the plastic coating is 1.31, the index of refraction of the glass this coating is placed on is 1.59 and the thickness of the glass is 1.53 mm. What thickness coating should be used? (in nm) A: 1.34×102 OB: 1.52x102 C: 1.71×102OD: 1.93x10²|OE: 2.19×102 F: 2.47×102 OG: 2.79×102|OH: 3.15×102 Submit Answer Tries 0/20

In order to protect eyes from damaging near ultraviolet light (UVA with wavlength of 397 nm), sunglasses are often coated so this light_is reflected. The index of refraction of the plastic coating is 1.31, the index of refraction of the glass this coating is placed on is 1.59 and the thickness of the glass is 1.53 mm. What thickness coating should be used? (in nm) A: 1.34×102 OB: 1.52x102 C: 1.71×102OD: 1.93x10²|OE: 2.19×102 F: 2.47×102 OG: 2.79×102|OH: 3.15×102 Submit Answer Tries 0/20

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter38: Refraction And Images Formed By Refraction

Section: Chapter Questions

Problem 127PQ: Light enters a prism of crown glass and refracts at an angle of 5.00 with respect to the normal at...

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Light enters a prism of crown glass and refracts at an angle of 5.00 with respect to the normal at the interface. The crown glass has a mean index of refraction of 1.51. It is combined with one flint glass prism (n = 1.65) to produce no net deviation. a. Find the apex angle of the flint glass. b. Assume the index of refraction for violet light (v = 430 nm) is nv = 1.528 and the index of refraction for red light (r = 768 nm) is nr = 1.511 for crown glass. For flint glass using the same wavelengths, nv = 1.665 and nr = 1.645. Find the net dispersion.
A source emits monochromatic light of wavelength 495 nm in air. When the light passes through a liquid, its wavelength reduces to 434 nm. What is the liquid's index of refraction? (a) 1.26 (b) 1.49 (c) 1.14 (d) 1.33 (e) 2.03
A soap bubble is blown outdoors. What colors (indicate by wavelengths) of the reflected sunlight are seen enhanced? The soap bubble has index of refraction 1.36 and thickness 380 nm.
Equation 24.14 assumes the incident light is in air. If the light is incident from a medium of index n1 onto a medium of index n2, follow the procedure used to derive Equation 24.14 to show that tan p = n2/n1.
The index of refraction for crown glass is 1.512 at a wavelength of 660 nm (red), whereas its index of refraction is 1.530 at a wavelength of 410 nm (violet). If both wavelengths are incident on a slab of crown glass at the same angle of incidence, 60.0, what is the angle of refraction for each wavelength?
A horizontal laser beam of wavelength 632.8 nm has a circular cross section 2.00 nun in diameter. A rectangular aperture is to lie placed in the center of the beam so that when the light falls perpendicularly on a wall 4.50 m away, the central maximum fills a rectangle 110 mm wide and 6.00 mm high. The dimensions are measured between the minima bracketing the central maximum. Find the required (a) width and (b) height of the aperture. (c) Is the longer dimension of the central bright patch in the diffraction pattern horizontal or vertical? (d) Is the longer dimension of the aperture horizontal or vertical? (e) Explain the relationship between these two rectangles, using a diagram.
An optical fiber has an index of refraction n and diameter d. It is surrounded by vacuum. Light is sent into the fiber along its axis as shown in Figure P34.31. (a) Find the smallest outside radius Rmin permitted for a bend in the fiber if no light is to escape. (b) What If? What result does part (a) predict as d approaches zero? Is this behavior reasonable? Explain. (c) As n increases? (d) As n approaches 1? (c) Evaluate Rmin assuming the fiber diameter is 100 m and its index of refraction is 1.40. Figure P34.31