In response to the answer for the question: uess the value of the limit (if it exists) by evaluating the function at the given numbers (correct to six decimal place) Lim x-> 2 (x^2 - 2x) / (x^2 - x - 2) 2.5, 2.1, 2.05, 2.01, 2.005, 2.001, 1.9, 1.95, 1.99, 1.995, 1.999) This is confusing. For the first one, 2.5. I input the 2.5 to the equation Lim x-> 2 (x^2 - 2x) / (x^2 - x - 2) and got -0.070922. Is that correct?

In response to the answer for the question: uess the value of the limit (if it exists) by evaluating the function at the given numbers (correct to six decimal place) Lim x-> 2 (x^2 - 2x) / (x^2 - x - 2) 2.5, 2.1, 2.05, 2.01, 2.005, 2.001, 1.9, 1.95, 1.99, 1.995, 1.999) This is confusing. For the first one, 2.5. I input the 2.5 to the equation Lim x-> 2 (x^2 - 2x) / (x^2 - x - 2) and got -0.070922. Is that correct?

College Algebra (MindTap Course List)

12th Edition

ISBN:9781305652231

Author:R. David Gustafson, Jeff Hughes

Publisher:R. David Gustafson, Jeff Hughes

Chapter4: Polynomial And Rational Functions

Section4.2: Polynomial Functions

Problem 96E: What is the purpose of the Intermediate Value Theorem?

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