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In tests of a computer component, it is found that the mean time between failures is 920 hours. A modification Is made which iS supposed to increase reliability by increasing the time between failures. Tests on a sample of 36 modified components produce a mean time between failures of 966 hours. Using a 5% level of significance, perform a hypothesis test to determine whether the mean time between failures for the modified components is greater than 920 hours. Assume that the population standard deviation is 51 hours. Ho : u>966 hours H: u= 966 hours OTest statistic : z= 108.24 Critical value :z=2.33 Reject the null hypothesis. There is sufficient evidence to support the claim that, for the modified components, the mean time between failures is greater than 966 hours. Ho : u = 966 hours H:u> 966 hours O Test statistic : z=5.41 Critical value :z=1.65 Reject the null hypothesis. There is sufficient evidence to support the claim that, for the modified components, the mean time between failures is greater than 966 hours. H:u=920 hours H:u>920 hours

In tests of a computer component, it is found that the mean time between failures is 920 hours. A modification Is made which iS supposed to increase reliability by increasing the time between failures. Tests on a sample of 36 modified components produce a mean time between failures of 966 hours. Using a 5% level of significance, perform a hypothesis test to determine whether the mean time between failures for the modified components is greater than 920 hours. Assume that the population standard deviation is 51 hours. Ho : u>966 hours H: u= 966 hours OTest statistic : z= 108.24 Critical value :z=2.33 Reject the null hypothesis. There is sufficient evidence to support the claim that, for the modified components, the mean time between failures is greater than 966 hours. Ho : u = 966 hours H:u> 966 hours O Test statistic : z=5.41 Critical value :z=1.65 Reject the null hypothesis. There is sufficient evidence to support the claim that, for the modified components, the mean time between failures is greater than 966 hours. H:u=920 hours H:u>920 hours

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 1GP
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In tests of a computer component, it is found that the mean time between failures is 920 hours. A modification is made which is supposed to increase reliability by increasing the time between failures. Tests on a sample of 36 modified components produce a mean time between failures of 966 hours. Using a 5% level of significance, perform a hypothesis test to determine whether the mean time between failures for the modified components is greater than 920 hours. Assume that the population standard deviation is 51 hours. H,: u>966 hours H: u=966 hours O Test statistic : z= 108.24 Critical value : z=2.33 Reject the null hypothesis. There is sufficient evidence to support the claim that, for the modified components, the mean time between failures is greater than 966 hours. H:u= 966 hours H: µ> 966 hours O Test statistic : z= 5.41 Critical value : z= 1.65 Reject the null hypothesis. There is sufficient evidence to support the claim that, for the modified components, the mean time between failures is greater than 966 hours. Ho: u=920 hours H: u>920 hours O Test statistic: z 5.41 Critical value : z=1.65 Reject the null hypothesis. There is sufficient evidence to support the claim that, for the modified components, the mean time between failures is greater than 920 hours. H: u> 966 hours H: u= 966 hours OTest statistic : z=5.41 Critical value:z=2.33 Reject the null hypothesis. There is sufficient evidence to support the claim that, for the modified components, the mean time between failures is greater than 966 hours.
Transcribed Image Text:In tests of a computer component, it is found that the mean time between failures is 920 hours. A modification is made which is supposed to increase reliability by increasing the time between failures. Tests on a sample of 36 modified components produce a mean time between failures of 966 hours. Using a 5% level of significance, perform a hypothesis test to determine whether the mean time between failures for the modified components is greater than 920 hours. Assume that the population standard deviation is 51 hours. H,: u>966 hours H: u=966 hours O Test statistic : z= 108.24 Critical value : z=2.33 Reject the null hypothesis. There is sufficient evidence to support the claim that, for the modified components, the mean time between failures is greater than 966 hours. H:u= 966 hours H: µ> 966 hours O Test statistic : z= 5.41 Critical value : z= 1.65 Reject the null hypothesis. There is sufficient evidence to support the claim that, for the modified components, the mean time between failures is greater than 966 hours. Ho: u=920 hours H: u>920 hours O Test statistic: z 5.41 Critical value : z=1.65 Reject the null hypothesis. There is sufficient evidence to support the claim that, for the modified components, the mean time between failures is greater than 920 hours. H: u> 966 hours H: u= 966 hours OTest statistic : z=5.41 Critical value:z=2.33 Reject the null hypothesis. There is sufficient evidence to support the claim that, for the modified components, the mean time between failures is greater than 966 hours.
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