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In the Bombay
What is the probability that a child will test as type AB blood from parents with the following genotypes?
IAIO Hh X IBIA hh
| 3/16 |
| 1/8 |
| 1/4 |
| 3/4 |
| 1/2 |
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- As it turned out, one of the tallest Potsdam Guards had an unquenchable attraction to short women. During his tenure as guard, he had numerous clandestine affairs. In each case, children resulted. Subsequently, some of the childrenwho had no way of knowing that they were relatedmarried and had children of their own. Assume that two pairs of genes determine height. The genotype of the 7-foot-tall Potsdam Guard was A9A9B9B9, and the genotype of all of his 5-foot clandestine lovers was AABB. An A9 or B9 allele in the offspring each adds 6 inches to the base height of 5 feet conferred by the AABB genotype. a. What were the genotypes and phenotypes of all the F1 children? b. Diagram the cross between the F1 offspring, and give all possible genotypes and phenotypes of the F2 progenyAn allele responsible for Marfan syndrome Section 13.4 is inherited in an autosomal dominant pattern. What is the chance that a child will inherit the allele if one parent does not carry it and the other is heterozygous?In the Bombay phenotype, a homozygous recessive individual hh appears to have blood type O because she is unable to produce the H substance, which is required to make the A or B blood-type antigens. HH or Hh individuals normally produce H substance. What is the probability that a child will test as type A blood from parents with the following genotypes? IAIO Hh X IBIO Hh 3/16 7/16 1/2 1/4 3/4
- In the Bombay phenotype, a homozygous recessive individual hh appears to have blood type O because she is unable to produce the H substance, which is required to make the A or B blood-type antigens. HH or Hh individuals normally produce H substance. What is the probability that a child will test as type AB blood from parents with the following genotypes? IAIO Hh X IBIO Hh 1/4 3/4 3/16 1/2 7/16A type B woman is the daughter of a type O father and type B mother. If she has children with a type O man, what are the following probabilities? A type AB child A type O child The first three children with type B blood A family containing two children with type B blood and one child with type OA woman who has blood type A positive has a daughter who is type O positive and a son who is type B negative. Rh positive is a trait that shows simple dominance over Rh negative and is designated by the alleles R and r, respectively. A third gene for the MN blood group has codominant alleles M and N. If both children are of blood type M in addition to their ABO blood type, list all of the possible parental phenotypes for the ABO, MN and Rh traits.
- A man with the II (A) blood group and a woman with the III (B) blood group in the AB0 system have black hair. Their child has blond hair and the I (0) blood group. What is the probability of the birth of a child with the father’s phenotype?A woman who has blood type A positive has a daughter who is type O positive and a son who is type B negative. Rh positive is a trait that shows simple dominance over Rh negative and is designated by the alleles R and r, respectively. A third gene for the MN blood group has co dominant alleles M and N. If both children are of blood type M in addition to their ABO blood type, list all of the possible parental phenotypes for the ABO, MN and Rh traits.Jay has type O blood, and his brother Alon has type AB blood. What are the genotypes of these boys’ parents? a. IAi and IBi b. IAi and IBIB c. IAIA and IBi d. ii and IBi e. It is not possible to determine the genotypes of the boys’ parents from the information provided.
- Albinism is a recessive disorder where there is a lack of melanin. Andrea and her husband Claude both have normal skin pigmentation. Andrea’s mother has the albino phenotype, but her father and her brother do not (normal pigmentation). Claude’s parents are both normal, but he has a sister who has the condition (is albino). Answer the following questions If Andrea and Claude are carriers for the albino allele, what is the probability that they have an albino child? If Andrea and Claude have a second child, what is the probability this child be normal (non-albino)? NOTE: Draw a punnet square or show your work.Sickle cell anemia is caused by an individual carrying two recessive copies of the hemoglobin gene (hemoglobin gene is labeled Hb, and the recessive version is Hbs). Thus, to have sickle cell anemia, a person must have the genotype HbSHbS. A person that is HbAHbA carries two copies of the normal hemoglobin gene and does not have sickle cell anemia. A person that is heterozygous (HbAHbS) produces enough normal hemoglobin to not have sickle cell anemia but is also resistant to malaria. People that are heterozygous are called “carriers” because they carry the recessive allele but do not express the recessive phenotype. a. A couple are both resistant to malaria but do not have sickle cell anemia. Draw a Punnett square to represent this cross. b. What is the probability that the couple has three children where one child does not have a recessive allele, one child is resistant to malaria and does not have sickle cell anemia, and one child has sickle cell anemia?Given that the normal hemoglobin allele (H) is dominant to the sickle-cell allele (h), each time two Hh individuals have a child together, what is the chance that the child will have sickle-cell disease? (a) 0% (b) 75% (c) 25% (d) 50% (e) 100%
