IN THE C PROGRAMMING LANGUAGE j = 15; k = 9 // what are the values for n,m,and p after these operations: --j ; k++ ; n = j - ++k; m = j-- + k--; p = k + j;
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IN THE C
j = 15; k = 9 // what are the values for n,m,and p after these operations:
--j ;
k++ ;
n = j - ++k;
m = j-- + k--;
p = k + j;
Step by step
Solved in 2 steps
- (Computation) Among other applications, Pascal’s triangle (see Figure 7.22) provides a means of determining the number of possible combinations of n things taken r at a time. For example, the number of possible combinations of five people (n = 5) taken two at a time (r=2)is10. Each row of the triangle begins and ends with 1. Every other element in a row is the sum of the element directly above it with the element to the left of the one above it. That is, element[n][r]=element[n1][r]+element[n1][r1] Using this information, write and test a C++ program to create the first 11 rows of a twodimensional array representing Pascal’s triangle. For any given value of n less than 11 and r less than or equal to n, the program should display the correct element. Use your program to determine in how many ways a committee of 8 can be selected from a group of 10 peopleWrite in C language Description 請寫一個程式找到三個數的最大公因數。 Please write a program to find the greatest common divisor of three number. Input 輸入會包含多筆測試資料,每筆測試資料一行,每行中有三個正整數,整數間會用一個空白隔開。 Input consist several test case, each test case a line. For every test case there are three integer in it and separate by a space. Output 對每一筆測試資料輸出一行結果。 For each test case output the result in one line. Sample Input 1 3 6 9 10 15 20 Sample Output 1 3 5EXPLAIN THIS C++ PROGRAM STEP BY STEP DETAIL WITH LOGIC #include<iostream> using namespace std; class Circle{int x,y;int r;static int number_of_circles;public:Circle(int a , int b, int rad){x = a;y = b;r = rad;++number_of_circles;}Circle(const Circle &c1){x = c1.x;y = c1.y;r = c1.r;number_of_circles = ++c1.number_of_circles; }void display(){cout<<"Co-ordinates : ("<<x<<" , "<<y<<" ) \n";cout<<"Radius : "<<r<<"\n";}friend void update(Circle &c);static int update_number_of_circles(){return number_of_circles;}};void update(Circle &c){int a,b,rad;cout<<"Enter the coordinates of the centre : ";cin>>a>>b;cout<<"Enter the radius of th circle : ";cin>>rad;c.x = a;c.y = b;c.r = rad;}int Circle::number_of_circles = 0; int main(){Circle c(1,2,5);Circle c1(c);Circle c2(c1);c1.display();update(c1);c1.display();cout<<c2.update_number_of_circles(); } #include<iostream> using namespace std;…
- Write a C++ program that takes a number N as input, and prints a sequence of numbers. The first term in this sequence should be N. The second term should be calculated using the following scheme: If the term is even, the next term is N/2. If the term is odd, the next term is 3N+1. The third term is calculated from the second term using the same scheme. The fourth term is calculated from the third term using the same scheme, and so on. You should stop when the last term you have printed is 1. Your code should also print the total number of terms in the sequence. (Use While loop)convert this in C language #include <iostream> using namespace std; int main(){cout << 1 << "," << 5;for (int i = 2, j = 4; i < 6; i++, j--){cout <<","<< i << "," << j;}cout << "\n";system("pause");return 0;}The factorial of a nonnegative integer n is written n! (pronounced as n factorial) and is defined as follows: n! = n * (n-1) * (n-2)….*1 (for values of n greater than or equal to 1) and n! = 1 (for n=0). Write a C++ program that reads nonnegative integer and compute and prints its factorial.
- In C language 2520 is the smallest number that can be divided by each of the numbers from 1 to 10 withoutany remainder. What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?Write in C language not C++ Description A mathmatician Goldbach's conjecture: any even number(larger than 2) can divide into two prime number’s sum.But some even numbers can divide into many pairs of two prime numbers’ sum. Example:10 =3+7, 10=5+5, 10 can divide into two pairs of two prime number. Input Input consist a positive even number n(4<=n<=32766). Output Print the value of how many pairs are this even number can be divided into. Sample Input 1 1234 Sample Output 1 25Convert the following C++ programs into Pep/9 assembly language: void minimum (int i1, int i2) { if (i1 < i2) cout << i1 << " is less than " << i2 << endl; else if (i2 < i1) cout << i2 << " is less than " << i1 << endl; else cout << i1 << " equals " << i2 << endl; } int main () { int n, m; cout << "Enter two integers: "; cin >> n >> m; minimum (n, m); return 0; }
- Please write in C language Description Please write a program for prime factorization. Input (please pay attention this this. Look at sample input 1 for example) Input consist several numbers. User must Input 0 to end. Output (look at sample output for example. Output must be exatcly the same including spacing and asterisks ) Please reference the sample output. Sample Input 1 12 81 0 Sample Output 1 12 = 2 * 2 * 3 81 = 3 * 3 * 3 * 3Write in C language Description Write a program to determine if a string is apalindrome or not. Input Input string will include only letter,please consider uppercase and lowercase as the same. Output Please refer to the sample output. Sample Input 1 AbcBa Sample Output 1 AbcBa is a palindrome. Sample Input 2 AAaab Sample Output 2 AAaab is not a palindrome.Need Help solving this in C++ language . Prompt for and get the user’s number of donuts to buy and the number of people who will be attending ameeting. Then print the information as shown below: Number of donuts = 23Number of people = 6Each person gets 3 donutsThere will be 5 donuts left