In the circuit shown below, R = 200.0 Q, C = 6.00 µF and the AC source is given by e = 170.0 sin (377t), where e is in volts and t is in seconds. The magnitude of phase angle between the current and the source voltage is: (AC) R O a. 65.6 degrees O b. 35.0 degrees O c. 45.0 degrees O d. 60.0 degrees O e. 72.4 degrees

In the circuit shown below, R = 200.0 Q, C = 6.00 µF and the AC source is given by e = 170.0 sin (377t), where e is in volts and t is in seconds. The magnitude of phase angle between the current and the source voltage is: (AC) R O a. 65.6 degrees O b. 35.0 degrees O c. 45.0 degrees O d. 60.0 degrees O e. 72.4 degrees

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter15: Alternating-current Circuits

Section: Chapter Questions

Problem 49AP: The emf of an ac source is given by v(t)=V0sint, where V0=100V and =200 . Find an expression that...

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