In the connection shown in Figure 5, ASTM A572 Grade 50 steel is used for tension member (C10-20), A36 steel is used for the gusset plate (t = ½ in.). The holes are for 1-inch bolts. What is the maximum factored block shear strength in LRFD for this connection? Note: You must check both, the tension member and the gusset plate, for block shear.
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- Two steel plate tension members have been connected using 0.72 inch diameter bolts arranged in an equally-spaced 9 by 3 rectangular formation. Both plates have a thickness equal to 1/3 in. Take shear fracture stress as 51.2 ksi, clear distance for each edge bolt as 0.12 in, and the clear distance for the other bolts as 1.072 in. a)Sketch the connection showing all the details and measurements with units. b)Find the maximum allowable service dead load and live load assuming live load is half as much as dead load. Consider ASD.For the splice connection shown in the figure, a. Check all spacing and edge-distance requirements. (For 1-in diameter bolts minimum edge distance is 1.25 in. AISC Table J3.4) b. Compute the design strength based on shear and bearing. (Use LRFD) The plates are PL 1/2" x 7" steel ASTM A36 (Fy = 36 ksi, Fu = 58 ksi) and the bolts are 1-in diameter A325X (Fnv = 60 ksi) in standard holes.Use ASD to determine the width of the 5/8 inch thick A36 plate subjected to tension as shown below. The dead load effect is PD=85 kip while the live load effect is PL=80 kip. Two rows of 5/8 inch standard bolts will be used for the connection and the plate width can be manufactured in 1 inch increments. Assume that the larger connected plate does not fail. Consider the limit states of gross tensile yield and tensile rupture. Find the required tension strength, Pa, for the controlling ASD load combination. Determine the width necessary for the plate to resist gross tensile yield. Determine the width necessary for the plate to resist tensile rupture. Report the required plate width.
- A 1 ⁄2 × 5-inch plate of A588 steel is used as a tension member. It is connected to a gusset plate with four 5 ⁄8-inch-diameter bolts as shown in Figure 1. Assume that the effective net area Ae equals the actual net area An. (a) Calculate the design strength for LRFD? (b) Calculate the allowable strength for ASD?A double lap splice connection shown in figure B is made up of 6mm x 150mm and 9mm x 150mm. Use NSCP specifications and assume a double row of bolts with standardsize holes for a bearing type connection with threads excluded from the shear planes.Minimum tensile strength Fu = 552.93MPa. Assume diameter hole is 3mm bigger than thediameter of bolts. Allowable shear stress is Fv = 207MPa. Allowable bearing stress fb = 1.2Fu.Diameter of bolts is 19mm. Fy = 449.25MPa.(a) Compute the tensile capacity of the steel plates. (Max. Net Area = 0.85 of Gross Area)(b) Compute the number of 19mm diameter bolts to develop the full strength of the plates. Note: SHOW DRAWINGS AND SOLUTIONS.Two plates each with thickness t = 5 mm are bolted together with 6 - 22 mm diameter bolts forming a lap connection. Plate (A36): Fy = 248 Mpa FU = 400 MPa bolts are A325 in standard holes with threads excluded from shear planes. Considering Tension Rupture, compute the the design strength for LFRD. Use NSCP 2015
- the design shear strength phi rnv of one A325-X bolt (Group A, X type), 7/8 inch in diameter in double shear is equal to: 46.8 kips 30.7 kips 27.9 kips or 61.3 kipsConsider the tension member shown below. The channel is made of ASTM A572 (Fy = 50 ksi; Fu = 65 ksi), and is connected to a 3/8-inch thick gusset plate made of ASTM A36 steel (Fy = 36 ksi; Fu = 58 ksi). The bolts are 7/8 inch in diameter, made of ASTM A307 bolts. The bolted connection is bearing-type. (a) Check if the given connection follows the code provisions on spacing and edge distance limits. (b) Determine the maximum allowable service tensile load that the member is allowed to carry. Consider all applicable limit states for tension member and connection. Consider only block shear and bearing limit state for gusset plate. Use ASD specifications. use AISC book (3decimals) PLEASEEE.Consider the tension member shown below. The channel is made of ASTM A572 (Fy = 50 ksi; Fu = 65 ksi), and is connected to a 3/8-inch thick gusset plate made of ASTM A36 steel (Fy = 36 ksi; Fu = 58 ksi). The bolts are 7/8 inch in diameter, made of ASTM A307 bolts. The bolted connection is bearing-type. (a) Check if the given connection follows the code provisions on spacing and edge distance limits. (b) Determine the maximum allowable service tensile load that the member is allowed to carry. Consider all applicable limit states for tension member and connection. Consider only block shear and bearing limit state for gusset plate. Use LRFD specifications. use AISC book
- A double-angle shape is shown in the figure. The steel is A36, and the holes are for 1/2-inch-diameter bolts. Assume the Ae = 0.75An.a) Determine the allowable tensile strength for ASD.b) Determine the design tensile strength for LRFD.The design shear strength phi rnv of one A490 X-bolt, 3/4 inch in diameter (Group B, X type) in single shear is equal to: Group of answer choices 39.8 kips 66.2 kips 27.8 kips 55.7 kipsA C15x40 channel section is bolted to a gusset plate is used to resist a tensile loadPu =313 k. The bolts are 3/4 inch diameter bolts A325 N (Group A, N Type) used insingle shear to resist this load. The bolts are to be symmetric and arranged in 3 rows.1) Determine the number of bolts needed for this connection. Draw a detailshowing how the bolts are arranged and showing spacing and edge distances onthis connection. Assume edge distance Le = 1.75db , use Le to nearest 1/4 in.2) If the connection is to be replaced by a fillet welded connection with transversewelds only along the channel web, determine the required fillet size to thenearest 16th of an inch.