In the figure, QS is a diameter of the circle. PQ= PR and ZPRQ = 72°. (a) Find ZSRP. 720 (b) Find ZSQR.

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
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In the figure, QS is a diameter of the circle. PQ = PR and ZPRQ = 72°.
(a) Find ZSRP.
S
72°
(b) Find ZSQR.
Transcribed Image Text:In the figure, QS is a diameter of the circle. PQ = PR and ZPRQ = 72°. (a) Find ZSRP. S 72° (b) Find ZSQR.
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