In the figure, the block of mass 2.00 kg accelerates down the inclined plane. The coefficient of kinetic friction is 0.200 and angle of the inclined plane is 30.00. What is the acceleration of the block? mg sine normal force N 0 O 4.05 m/s2 Ⓒ2.05 m/s² Ⓒ 3.05 m/s² Ⓒ 5.05 m/s² 0 mg friction force f mg cost

In the figure, the block of mass 2.00 kg accelerates down the inclined plane. The coefficient of kinetic friction is 0.200 and angle of the inclined plane is 30.00. What is the acceleration of the block? mg sine normal force N 0 O 4.05 m/s2 Ⓒ2.05 m/s² Ⓒ 3.05 m/s² Ⓒ 5.05 m/s² 0 mg friction force f mg cost

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter4: The Laws Of Motion

Section: Chapter Questions

Problem 6OQ

See similar textbooks

Similar questions

The systems shown in Figure P4.58 are in equilibrium. If the spring scales are calibrated in newtons, what do they read? Ignore the masses of the pulleys and strings and assume the pulleys and the incline in Figure P4.58d are frictionless. Figure P4.58
In the situation described in Problem 45 and Figure P4.45, the masses of the rope, spring balance, and pulley are negligible. Nicks feet are not touching the ground. (a) Assume Nick is momentarily at rest when he stops pulling down on the rope and passes the end of the rope to another child, of weight 440 N, who is standing on the ground next to him. The rope does not break. Describe the ensuing motion. (b) Instead, assume Nick is momentarily at rest when he ties the end of the rope to a strong hook projecting from the tree trunk. Explain why this action can make the rope break. Figure P4.45 Problems 45 and 46.
A block of ice (m = 15.0 kg) with an attached rope is at rest on a frictionless surface. You pull the block with a horizontal force of 95.0 N for 1.54 s. a. Determine the magnitude of each force acting on the block of ice while you are pulling. b. With what speed is the ice moving after you are finished pulling? Repeat Problem 71, but this time you pull on the block at an angle of 20.0.
A 3.00-kg object is moving in a plane, with its x and y coordinates given by x = 5t2 1 and y = 3t3 + 2, where x and y are in meters and t is in seconds. Find the magnitude of the net force acting on this object at t = 2.00 s.
According to a simplified model of a mammalian heart, at each pulse, approximately 20 g of blood is accelerated from 0.26 m/s to 0.35 m/s during a period of 0.10 s. What is the magnitude of the force exerted by the heart muscle? Express your answer to two significant figures and include the appropriate units. F= ______ units I got 0.02N but it is wrong.
A horizontal force, F_{1} = 55N and a force, F_{2} = 12.5N acting at an angle of to the horizontalare applied to a block of mass m = 4.5kg The coefficient of kinetic friction between the block and the surface is u_{k} = 0.2 The block is moving to the right Solve numerically for the magnitude if acceleration of yhe block , - in m/s^2 if 0=30 degrees
There are two forces on the 1.19 kg box in the overhead view of the figure but only one is shown. For F1 = 15.7 N, a = 14.7 m/s2, and θ = 34.1°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.)
Two forces, F1 and F2, act on the 7.00-kg block shown in the drawing. The angles made by the forces with horizontal are equal to 40 degrees. The magnitudes of the forces are F1= 59 0 N and F2 = 49.0 N. The coefficient of kinetic friction between the block and the surface is 0.1.
Q4/ a force vector F =3i + 3j is applied on 5 kg mass of body on nonfrictionless horizontal surface. The displacement function of body is x= t3 + t +1 .find the coefficient of friction. ( 15 deg.)
A block of mass 20kg is pushed against a vertical wall by force P. The coefficient of friction between the surface and the block is 0.2. If theta = 30 degrees, what is the minimum magnitude of P to hold the block still?I understand that in order for the block to sit motionless, the net forces acting on the block must be zero. I set my equation to be Net Force = 0 = Psin(theta) + Force Friction - Force Gravity.Which I rearranged as P = (Force Gravity - Force Friction)/sin(theta) or P = (mg-μ(mg))/sin(theta)Doing this gives me a value of 313.6N rather than 202.9N which I should be getting. What am I doing wrong?
In the figure, a slab of mass m1 = 40 kg rests on a frictionless floor, and a block of mass m2 = 10 kg rests on top of the slab. Between block and slab, the coefficient of static friction is 0.60, and the coefficient of kinetic friction is 0.40. A horizontal force F→ of magnitude 104 N begins to pull directly on the block, as shown. In unit-vector notation, what are the resulting accelerations of (a) the block and (b) the slab?
If a box with mass of 50 kg is moving on a rough surface with kinetic friction coefficient of 0.7, how much force is needed to keep the box moving? Group of answer choices 343 N 35 N 490 N 6.7 N