In the figure, the net external force on the 24 kg mower is known to be 51 N. f=28N v=1.8 m/s   a. If the force of friction opposing the motion of 28N what force in newtons is the person acting on the mower? b. Suppose the mower is moving at 1.8 m/s when the force F is removed. How far will the mower go before stopping in m?

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A: D = 15.8 kmθ = 51.2°

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Q: Two charges q1 = +2.27 μC and q2 = +8.2 μC are separated by a distance of 19.49 cm. Point P is…

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A: Given, height 1= 25 m initial velocity= 0 m/s height 2 = ?final velocity = 12.5 m/s

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Newton's Second Law

Newton’s laws of motion describe the relationship between the motion of an object and forces acting on it. Newton’s law of motion has two types as follows: