In the left-hand tank in Fig. 2-24, the air pressure is -9 in of mercury. Determine the elevation of the gage liquid in the right-hand column at A. Ans. elevation 86.7 ft 2.86 psi Air 120.0 Air Oil 112.0' (sp gr 0.80) Water 106.0 sp gr 1.60 Fig. 2-24

International Edition---engineering Mechanics: Statics, 4th Edition
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Chapter8: Centroids And Distributed Loads
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2.36. In the left-hand tank in Fig. 2-24, the air pressure is-9 in of mercury. Determine the elevation of the gage
liquid in the right-hand column at A.
Ans. elevation 86.7 ft
2.86 psi
Air
120.0
Air
Oil
(sp gr 0.80)
112.0'
Water
– 106.0'
sp gr 1.60
Fig. 2-24
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Transcribed Image Text:2.36. In the left-hand tank in Fig. 2-24, the air pressure is-9 in of mercury. Determine the elevation of the gage liquid in the right-hand column at A. Ans. elevation 86.7 ft 2.86 psi Air 120.0 Air Oil (sp gr 0.80) 112.0' Water – 106.0' sp gr 1.60 Fig. 2-24 Activate Windoys
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