In the subtropics the latent heat loss Qe at the sea surface is typically -125 W/m². How many meters of the water column would be evaporated each year? Assume seawater density p of 1,027 kg/m³ and latent heat of evaporation Le of 2472 x 10³ J/kg. Knowing that latent heat loss is Qe =Fe . Le where Fe is the evaporative rate [kg/(m² s)], i.e. mass (m) of water evaporated per unit area (a) and time (t).

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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In the subtropics the latent heat loss Qe at the sea surface is typically -125 W/m?. How
many meters of the water column would be evaporated each year? Assume seawater
density p of 1,027 kg/m³ and latent heat of evaporation Le of 2472 x 10³ J/kg.
Knowing that latent heat loss is Qe = Fe . Le
where Fe is the evaporative rate [kg/(m² s)], i.e. mass (m) of water evaporated per unit
area (a) and time (t).
Transcribed Image Text:In the subtropics the latent heat loss Qe at the sea surface is typically -125 W/m?. How many meters of the water column would be evaporated each year? Assume seawater density p of 1,027 kg/m³ and latent heat of evaporation Le of 2472 x 10³ J/kg. Knowing that latent heat loss is Qe = Fe . Le where Fe is the evaporative rate [kg/(m² s)], i.e. mass (m) of water evaporated per unit area (a) and time (t).
Expert Solution
Step 1

Given

Latent heat, Lh=-125 Wm2

Density=1027 kgm3

Latent heat of evaporation, Le=2472 x 103 Jkg

 

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