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In the transportation problem, if the number of allocation is less than m+n-1 then it is called as non-degenerate basic feasible solution. In the transportation problem, the lowest cost entry method depend on determining the smallest cost in the cost matrix of the transportation table and allocate xij=min (ai,bj) in the cell (ij). For an assignment problem with 3 agents and 4 tasks, the assignment matrix will have 3 rows and 4 columns.

In the transportation problem, if the number of allocation is less than m+n-1 then it is called as non-degenerate basic feasible solution. In the transportation problem, the lowest cost entry method depend on determining the smallest cost in the cost matrix of the transportation table and allocate xij=min (ai,bj) in the cell (ij). For an assignment problem with 3 agents and 4 tasks, the assignment matrix will have 3 rows and 4 columns.

College Algebra
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter6: Matrices And Determinants
Section: Chapter Questions
Problem 4CC
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In the transportation problem, if the number of allocation is less than m+n-1 then it is called as non-degenerate basic feasible solution. In the transportation problem, the lowest cost entry method depend on determining the smallest cost in the cost matrix of the transportation table and allocate xij=min (ai,bj) in the cell (ij). For an assignment problem with 3 agents and 4 tasks, the assignment matrix will have 3 rows and 4 columns.
Transcribed Image Text:In the transportation problem, if the number of allocation is less than m+n-1 then it is called as non-degenerate basic feasible solution. In the transportation problem, the lowest cost entry method depend on determining the smallest cost in the cost matrix of the transportation table and allocate xij=min (ai,bj) in the cell (ij). For an assignment problem with 3 agents and 4 tasks, the assignment matrix will have 3 rows and 4 columns.
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