In the world series of baseball, two teams A & B play a sequence of games against each other and the first team that wins a total of four games become the winner of the world series. If the probability that team A will win any parties game against team B is 1/3, what's the probability that team A will win the world series?
In the world series of baseball, two teams A & B play a sequence of games against each other and the first team that wins a total of four games become the winner of the world series. If the probability that team A will win any parties game against team B is 1/3, what's the probability that team A will win the world series?
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.8: Probabilities Of Disjoint And Overlapping Events
Problem 2C
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Question
In the world series of baseball, two teams A & B play a sequence of games against each other and the first team that wins a total of four games become the winner of the world series. If the probability that team A will win any parties game against team B is 1/3, what's the probability that team A will win the world series?
Expert Solution
Step 1
Given that, the probability that team A will win any parties game against team B is 1/3 i.e.
p= 1/3
Team A wins if it wins the majority of 7 games
Thus, we've to compute the probability of winning 4, 5, 6 or 7 games out of 7.
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