In this program, you will check whether two dominoes match. Because you can flip a tile, two tiles match if the number on the left or right matches the left or right on the other tile. You should print all matches. First check a direct match, then try flipping tiles. But don’t flip a tile whose left and right numbers are the same. If there is no match, print "No match". For example, with the tiles 1 3 and 4 3, print 1 3 3 4

In the classic problem FizzBuzz, you are told to print the numbers from 1 to n. However,when the number is divisible by 3, print "Fizz''. When it is divisible by 5, print "Buzz''. When it isdivisible by 3 and 5, print"FizzBuzz''. In this problem, you are asked to do this in a multithreaded way.Implement a multithreaded version of FizzBuzz with four threads. One thread checks for divisibilityof 3 and prints"Fizz''. Another thread is responsible for divisibility of 5 and prints"Buzz''. A third threadis responsible for divisibility of 3 and 5 and prints "FizzBuzz''. A fourth thread does the numbers.

Write a program that asks the user to enter 10 numbers, that range from 0-100. Make sure that you do not accept any numbers less than 0, if a user enters a number that is less than 0 then ask him again. Once the user enters all 10 numbers, find and print out the median.   How to calculate the Median The median is the middle score of a distribution. To calculate the median Arrange your numbers in numerical order. Count how many numbers you have. If you have an odd number, divide by 2 and round up to get the position of the median number. If you have an even number, divide by 2. Go to the number in that position and average it with the number in the next higher position to get the median. Consider this set of numbers: 5, 7, 9, 9, 11. Since you have an odd number of scores, the median would be 9. You have five numbers, so you divide 5 by 2 to get 2.5, and round up to 3 (to round numbers in C#, use Math.Round()). The number in the third position is the median.   In this case, the mean…

Assignment4C: Heads or Tails? It is said that a perfectly fair coin will return heads 50% of the time, and tails 50% of the time. Rather than have you test this theory by flipping a coin yourself, let's use a random number generator and loops to determine the truth. Create a program that prompts the user for a number of coin flips. Then, “flip a coin" that many times by using a random number generator that produces either a 0 or 1. Afterwards, show the user how many times it landed on heads (0) and tails (1) and calculate the frequency for each. Inform the user if heads or tails was the more frequency result, or if they were equal. Call the file name Assignment4C (.java, .cs, .cpp) and the class name Assignment4C. Example outputs are shown below. Note that due to using a random number generator, you may not get the same numerical results – but the formatting and wording should be the same. User input is indicated in bold. Sample Output #1: How many times do you want to flip the coin?:…