In this Sn-Pb alloy system, what is the relative percentage of proeutectic alpha phase after alloy 2 is cooled down from 300 °C to room temperature?Alloy 2Alloy I327SolidusLiquidus300LiquidLiquidus250a + liquidSolidus200B+ liquid183Eutectic point150Solvus+B100Solvus5019.240.061.997.5li601020304050708090100%100%Weight percent tinSnPbO1. 73%O II. 51%O II. 49%O IV. 27%Temperature (C),

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Answered: In this Sn-Pb alloy system, what is the…

In this Sn-Pb alloy system, what is the relative percentage of proeutectic alpha phase after alloy 2 is cooled down from 300 °C to room temperature?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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List the phase(s) that are present, the phase composition(s) and the weight fractions of the phase(s) for each of the following alloys:(a) 70 wt% Zn-30 wt% Cu at 300 C (b) 90 wt% Pb-10 wt% Sn at 325 C (c) 2.5 kg Cu and 5.0 kg Ag at 900 C (d) 37 lbm Pb and 6.5 lbm Mg at 500 C
11.15) Make a copy of the isothermal transforma- tion diagram for an iron-carbon alloy of eutectoid composition (Figure 11.14) and then sketch and label on this diagram time- temperature paths to produce the following microstructures: (a) 100% coarse pearlite. (b) 100% tempered martensite. (c) 50% coarse pearlite, 25% bainite, and pearl- 25% martensite.
10.27 A hypothetical A-B alloy of composition 55 wt% B-45 wt% A at some temperature is found to consist of mass fractions of 0.5 for both a and 8 phases. If the composition of the B phase is 90 wt B-10 wt% A, what is the composition of the a phase?
Q.1.For hypoeutoctoid plain carbon steel(select %C content yourself), determine the phasesthat are present, the compositionsof these phases, and the percentages or fractionsof the phases.Make schematic sketches of the microstructurethat would be observed for conditions of very slow cooling at the following temperatures: a)Just above the austenite transformation temperature b)The austenite transformation temperature -10C c)The eutectoid transformation temperature +10C d)The eutectoid transformation temperature -10C
Calculate the amounts and compositions of phases at 726oC in a Fe-0.6% C alloy cooled under equilibrium conditions. Disregard the amounts of proeutectoid phases. A. 77.3% α, 22.7% Fe3C; C in α = 6.7% and C in Fe3C = 0.02% B. 91.3% α, 8.7% Fe3C; C in α = 0.02% and C in Fe3C = 6.7% C. 77.3% α, 22.7% Fe3C; C in α = 0.02% and C in Fe3C = 6.7% D. 91.3% α, 8.7% Fe3C; C in α = 0.05% and C in Fe3C = 8.4% E. None of the mentioned
For alloys of two hypothetical metals A and B, there exist an α, A-rich phase and a β, B-rich phase. From the mass fractions of both phases for two different alloys (given below), which are at the same temperature, determine the composition of the phase boundary (or solubility limit) for the following: Alloy Composition Fractionα Phase Fractionβ Phase 60 wt% A - 40 wt% B 0.57 0.43 30 wt% A - 70 wt% B 0.12 0.88 (a) α phase ________ wt% A (b) β phase ________ wt% A
From the phase diagram of the Fe-0.25wt%C alloy below, determine the phase fraction and elemental composition of the resulting phase immediately after solidification across the eutectoid line (725 C). a.alpha_eutectoid = 96.6 wt% and cementite = 29.85 wt% b.alpha_eutectoid = 96.6 wt% and cementite = 3.4 wt% c.alpha_eutectoid = 1.05 wt% and cementite = 29.85 wt% d.alpha_eutectoid = 29.85 wt% and cementite = 1.05 wt%
Choose the corect answer -A vertical line in the phase diagram represents a.an intermetallic compound b.a eutectic phase c.a eutectoid phase Match each statement with a letter -In the peritectoid reaction -In the Peritectic reaction: -In the Monotectic reaction: -In the Eutectoid reaction: -In the Eutectic reaction: a. a liquid phase transforms into two solids when it is cooled down b. a solid phase transforms into two different solids when it is cooled down c. a liquid phase transforms into a new liquid phase and a solid phase d. Two solid phases transform into a new single solid phase e. A solid phase and a liquid phase transforms into a solid phase
Q1/ The figure below shows the phase equilibrium diagram for copper and silver Answer the following paragraphs? Conpostin a% 39 o = « & o Tepertue (F) @ Composttan (w5 ) 0 1- define pointe E? 2- define pointe B? 3- define the line AE? 4- define the line BG? 5- define the line FG?
In a binary Fe-Fe3C system, what is a transformation that occurs when cooling an austenistic mixture of 2% C by weight from 1100°C to below the eutectoid temperature? What is the microstructure, and how is it formed? What are the total and partial phases? Given:Eutectoid temperature=723°C; Eutectoid concentration=0.76% C; Limit concentration of ferrite=0.022%; Limiting concentration of cementite: 6.7%.
An alloy of 30 wt % Pb and 70 wt % Sn is slowly cooled from 250°C to 27°C: a) Is this alloy hypoeutectic or hypereutectic? b) What is the composition of the first solid to form? c) What are the amounts and compositions of each phase that is present at 183°C + ∆T ? d) What is the amount and composition of each phase that is present at 183°C - ∆T ? e) What are the amounts of each phase present at room temperature? f) Draw the microstructure 183°C + ∆T and 183°C - ∆T in 2 cm diameter circle.
The Fe – Au solid – liquid T – xB phase diagram can be viewed as the intersection of asolid – phase miscibility gap with a solid – liquid phase – transition loop having aminimum at xAu = 0.8. The miscibility gap intersects the phase transition loop at xAu =0.1 and at xAu = 0.3. Fe has a higher melting point than Au. Sketch the phase diagramand label all the areas.