In Young's experiment, the electric fields of the waves arriving at point P are given by E1 = (5.00 µN/C) sin{(4.74 × 1015)t} E2 = (9.00 µN/C) sin{(4.74 × 1015)t + 21.1 rad}, where time t is in seconds. What is the amplitude of the resultant electric field at point P?

In Young's experiment, the electric fields of the waves arriving at point P are given by E1 = (5.00 µN/C) sin{(4.74 × 1015)t} E2 = (9.00 µN/C) sin{(4.74 × 1015)t + 21.1 rad}, where time t is in seconds. What is the amplitude of the resultant electric field at point P?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter24: Wave Optics

Section: Chapter Questions

Problem 69AP: Figure P24.69 shows a radio-wave transmitter and a receiver, both h = 50.0 m above the ground and d...

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Electromagnetic Waves

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Question

In Young's experiment, the electric fields of the waves arriving at point P are given by

E₁ = (5.00 µN/C) sin{(4.74 × 10¹⁵)t}

E₂ = (9.00 µN/C) sin{(4.74 × 10¹⁵)t + 21.1 rad},

where time t is in seconds. What is the amplitude of the resultant electric field at point P?

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