#7 Chem 1700 - Equations/Coeversions/Drats of interestK-C+ 27sA cm-1 inchI qtA kg-2.20 lb- hv-heh-6.626 x 10sse-2.x 10 msAPP -D mass/volumeW-nRT1J-1 kg m aMV- MV1M-rA-mol/Lm HgR-0.082058 8.314 mol 62.364STP- 1 atm (760 mmHg), 273L atm1 atm - 760. mmHg-760 torr- 101,325 Pa-14.7 psiNP.v, -The volume of one mole of gas at STP-22ALAPF -R-8.314-adro's number (NA)-6.02 x 10hx 10 kgFor the following: H2COState the number of valence electrons andDraw the Lewis Structure:oldet niwollol odi otslomo (g)State the electron domaingeometry and type of hybrid orbitalused?trigonal planerM-Orbital Diagram of central atom alone, (C):Orbital Diagram of central atom in molecule7.In your Lewis structure for above, label all the bonds as sigma or pi.a) how many sigma and pi bonds are represented?b) for the bonds between C and O in the Lewis structure on the previous page, dethe type of orbitals that overlap to form that bond.

Answered: Image /qna-images/answer/d6cbee17-c3b7-4cc4-9ebe-a2b6dbb1972a.jpg

Answered: In your Lewis structure for above,…

Appl Of Ms Excel In Analytical Chemistry

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ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter2: Basic Statistical Analysis With Excel

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Problem 12P

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Show all steps leading to the final answer po. Here’s a pdf file in accordance with the topic po: https://drive.google.com/file/d/1_FnDtXCrFKSol3RNWIG_9tNQ7IxgxD6t/view?usp=drivesdk
If 5 µM enzyme was used to obtain the data in the summary plot below, V-max = ________________ µM sec-1 and Km = ____________ µM for this enzyme (Enter numeric values to the nearest integer; Do NOT write units.)
Module Code & Title: CHM9011M Chromatography and Sep Sciences Section 1: Purpose Clarity of Purpose ): Clearly states the purpose of the SOP. Relevance to Task : Demonstrates the importance and relevance of the procedure. Alignment with Goals ): Shows how the procedure aligns with organisational goals.
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Sample IdentificationCodeConcentration of M%TA=2-log(%T)Q50004.00 x 10-417.90.75Q50013.20 x 10-425.00.6Q50022.40 x 10-435.70.46Q50031.60 x 10-450.20.3Q50048.000 x 10-570.80.15SampleIdentificationCode%TA=2-log(%T)AMQ0210150143.70.359518560.360.000192Q0210150244.10.355561410.360.00018Q0210150343.80.358525890.360.00017Q0210150444.10.355561410.360.00018Q0210150543.80.358525890.360.00017What was their percent error?43%Does Batch 021015 meet legal requirements?No, because it is not between 2.85 * 10(4) and 3.15 * 10(4)Well #DropsBluedye1234567891012345678910Drops 9Distilled water876543210Concne 0.26tration0.52Test Tube #0.781.041.3Solutions3Concentration (M)2.082.32.6Concentration (ppm)1:1 dilution11.82Starting Dilution21.562:1 dilution0A.Zero standard0Was your calibration curve as linear as you expected?B.Did you experience any â€œdriftâ€ of the resistance readings?C.What is the equation of your best-fit line?D.What commercial drink did you analyze?E.Assuming…
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In your Lewis structure for above, label all the bonds as sigma or pi. a) how many sigma and pi bonds are represented? 7. b) for the bonds between C and O in the Lewis structure on the previous page, de the type of orbitals that overlap to form that bond.