write comments to each line of code #include#includeint main(int argC, char * argvll){int x = argc-1:int num1[x]:int į = 1:int Sum = 0:for (i ik=x; i++){num1[i] = atoi (arsvlJ:Sum += num1[i]:}Rrintfl"Sum of Num1 and Num2 is : %d\n", Sum);return 0:} #include#include#includeint main(int argc.char *argyll){int n:int i:if(arge==1){Rrintil"\n\nPlease Enter the Arguments\n\n");return 0;}for(i=1; i

#include<stdio.h> /* header file for input output statement */ #include<stdlib.h> /*…

Answered: #include int main(int arge, char * argy…

Engineering

Computer Science

#include int main(int arge, char * argy { int x = argc-1; int num1[x]:

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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5: CheckLetter.cpp) Write a program that adds a checkletter to an eight-digit number. The check letter should becomputed as follows: Break the number up into 4 two-digitnumbers. Add the four numbers together. Find theremainder after division by 26. The check letter is the letterin the alphabet that corresponds to the number justcomputed. (A=0, B=1, C=2, etc.) Print the original numberfollowed by the check letter. Use at least one ffunction thatreturns a value when you write this program.
c++complete and change #include <iostream>using namespace std; int sumbyrow(int* m, int ncol, int row){int total = 0;for (int i = 0 i < ncol; i++) {total += m[row * ncol + i];}return total; } int sumBCol(int* m, int nrow, int ncol, int col){int total = 0;for (int j = 0; < j nrow; j++) {total += m[j * ncol + col]; }return total;}int sumBYLeftDiag(int* m, int ncol){int total = 0;for (int i = 0, j = ncol - 1; i < ncol && j >= 0; i++, j--) {total += m[i * ncol + j];}return total;}bool hasDuplicates(int* m, int row) {int flatArray[row * row];int k = 0for (int i = 0; i < row; i++) {for (int j = 0; j < row; j++) {flatArray[k++] = m[i * row + j]; }}for (int i = 0; i < (row * row); i++) {for (int j = i + 1; j < (row * row); j++) {if (flatArray[i] == flatArray[j])return true; }}return flase;} bool isMagicMatrix(int* m, int nrow, int ncol) { if (hasDuplicate(m, nrow), int ncol{return false; }if (sumByleftDiag(m, nrow) != sumByRightDiag(m, nrow)) {return…
int main(){ long long int total; long long int init; scanf("%lld %lld", &total, &init); getchar(); long long int max = init; long long int min = init; int i; for (i = 0; i < total; i++) { char op1 = '0'; char op2 = '0'; long long int num1 = 0; long long int num2 = 0; scanf("%c %lld %c %lld", &op1, &num1, &op2, &num2); getchar(); long long int maxr = max; long long int minr = min; if (op1 == '+') { long long int sum = max + num1; maxr = sum; minr = sum; long long int res = min + num1; if (res > maxr) { max = res; } if (res < minr) { minr = res; } } else { long long int sum = max * num1; maxr = sum; minr = sum; long long int res = min * num1;…
int fun(int k){ return ( ); void main(){ int n; cin >> n; n = n * fun(n); <-- 1 Fill in the appropriate statement and expression in fun, so that when it is called in main, and after the execution of the statement marked 1, the value of n would always be n3.
Individual Arguments is reference arguments that are in consecutive order True O False O
#include <iostream>#include<iomanip>using namespace std; int main(){ const int ROW_HOURS=6; //declare variables const int CL_PAYRATE=2; double total_payout=0; double hours[ROW_HOURS][CL_PAYRATE]={ //declare array {0,12.85}, {0,12.85}, {0,12.85}, {0,11.75}, {0,11.75}, {0,11.15} }; cout<<fixed; cout<<setprecision(2); //setprecision of double values upto 2 decimal point for(int i=0;i<6;i++) //using loop get input from user { cout<<"Enter the hours worked by employee "<<i+1<<": "; cin>>hours[i][0]; //store values into hours } for(int i=0;i<6;i++) { double payout=hours[i][0]*hours[i][1]; //calculate payout of emplyee total_payout=total_payout+payout;…
(Evaluate expression) Modify Listing 20.12, EvaluateExpression.java, to addoperators ^ for exponent and % for remainder. For example, 3 ^ 2 is 9 and 3% 2 is 1. The ^ operator has the highest precedence and the % operator has thesame precedence as the * and / operators. Your program should prompt theuser to enter an expression. Here is a sample run of the program: Enter an expression: (5 * 2 ^ 3 + 2 * 3 % 2) * 4(5 * 2 ^ 3 + 2 * 3 % 2) * 4 = 160 Here is the Listing 20.12 to modify: import java.util.Stack; public class EvaluateExpression { public static void main(String[] args) { // Check number of arguments passed if (args.length != 1) { System.out.println( "Usage: java EvaluateExpression \"expression\""); System.exit(1); } try { System.out.println(evaluateExpression(args[0])); } catch (Exception ex) { System.out.println("Wrong expression: " + args[0]); } } /** Evaluate an expression */ public static int evaluateExpression(String expression) { // Create operandStack to store operands…
Look at the following C++ code and comment each line about how it works with pointer. int i = 33; double d = 12.88; int * iPtr = &i; double * dPtr = &d; // iPtr = &d; // dPtr = &i; // iPtr = i; // int j = 99; iPtr = &j; //
This is the C code I have so far #include <stdio.h> #include <stdlib.h> struct employees { char name[20]; int ssn[9]; int yearBorn, salary; }; struct employees **emps = new employees()[10]; //Added new statement ---- bartleby // function to read the employee data from the user void readEmployee(struct employees *emp) { printf("Enter name: "); gets(emp->name); printf("Enter ssn: "); for(int i =0; i <9; i++) scanf("%d", &emp->ssn[i]); printf("Enter birth year: "); scanf("%d", &emp->yearBorn); printf("Enter salary: "); scanf("%d", &emp->salary); } // function to create a pointer of employee type struct employees *createEmployee() { // creating the pointer struct employees *emp = malloc(sizeof(struct employees)); // function to read the data readEmployee(emp); // returning the data return emp; } // function to print the employee data to console void display(struct employees…
#include <iostream>using namespace std;struct item{ int id; float price;} s[50];int size = 0;void addData() { cout << "Enter an item data " << endl; cout << "Enter id: "; cin >> s[size].id; cout << "Enter price: "; cin >> s[size].price; cout << "successfully added" << endl << endl; size++; for (int i = 0; i < size; i++) { for (int j = i + 1; j < size; j++) { if (s[i].price > s[j].price) { struct item t = s[i]; s[i] = s[j]; s[j] = t; } } }}void retrivePrice() { int id; cout << "enter the element id:"; cin >> id; cout << endl; int i; for (i = 0; i < size; ++i) { if (id == s[i].id) { cout << "price for this item: " << s[i].price << endl << endl; break; } } if (i == size) cout…
#include <iostream>using namespace std;struct item{ int id; float price;} s[50];int size=0; void addData(){ cout << "Enter an item data " << endl; cout << "Enter id: "; cin >> s[size].id; cout << "Enter price: "; cin >> s[size].price; cout<<"successfully added"<<endl<<endl; size++; for(int i=0;i<size;i++) { for(int j=i+1;j<size;j++) { if(s[i].price>s[j].price) { struct item t=s[i]; s[i]=s[j]; s[j]=t; } } }}void retrivePrice(){ int id; cout<<"enter the element id:"; cin>>id; cout<<endl; int i; for( i = 0; i < size; ++i) { if(id == s[i].id){ cout << "price for this item: " << s[i].price << endl<<endl;…
EXPLAIN THIS CODE EACH LINE #include <stdio.h>#include<string.h>int main(){ char name[20]; int meal,quantity; int drink,quantity2; char choose_meal[30] = ""; int meal_price; float drink_price, orderPrice; char choose_drink[30] = ""; float cash, change; printf("--------------------Marry's Fast Food--------------------"); printf("\n"); printf("Enter your name: "); scanf("%s", name); printf("Hello %s!\n", name); printf("\n\nWhat would you like to order?\n"); printf("------------------------MEALS------------------------\n\n"); printf("[1] 1 pc. Chicken Joy....................Php 76.00\n"); printf("[2] 1 pc. w/Jolly spaghetti..............Php 99.00\n"); printf("[3] pc. Spaghetti........................Php 55.00\n"); printf("[4] pc. Burger steak w/rice..............Php 85.00\n"); printf("[5] pc. Burger...........................Php 30.00\n\n"); printf("Choose a number…