ind the standard deviation (rounded to the nearest unit) for the data indicated. Test Score      Frequency 90   1         80   3         70   7         60   4         50   2

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A: Solution

Q: Part 2 of 4 The area of the interval lies between z = -0.82 and z=-0.42 is

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Q: 8 T 0. * 1 2 3 4 P(x) 0.06 0.15 0.45 0.21 0.13 Send data to Excel Part 1 of 3 (a) Find the…

A: Given:

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A: The provided information is  p=0.80 n=200 µ=np=0.81*200=162 σ=np(1-p)=200*0.81*0.19σ=5.548 a.…

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Q: В. 35 12.What is the sample size needed if the margin of error is 30 and th deviation of 45 with a…

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Q: D. Yes, because o is equal to s w 8. What will be the effect on the t distri A. The t-distribution…

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A: To determine: the value of f0.99(23,30)

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A: From the provided information, Number of observations (n) = 11 SSx = 6, SSy = 55 and SP = 8

Q: Ten subjects were chosen for an experiment. They were asked to perform a certain physical activity.…

A: Solution: Before  After d=After -Before (d-d )  (d-d )2 60 92 32 23.2 538.24 67 79 12 3.2…

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A: For online : sample size (n1) = 15 sample mean (x̄1) = Σx1 /n1 = 62/15 = 4.13 sample standard…

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Q: The area of the interval lies between z =-0.82 and z = -0.42 is | 0

A: area under normal curve represented by proabability

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A: The given values are 1, 9, 2, 12, 8, 7, and 10. The value of µ is 7 and σ2 is 3.7796.