# Indicate the answer choice that best comple tes the statement or answers the question.1. The electron in a hydrogen atom, originally in levelphoton of wavelength 3745 nm. What is the final level of the electron?(c-3.00x108 m/s, h=6.63x10-34 J.s, R 2.179x10-18 J)8, undergoes a transition to a lower level by emitting aa. 5b. 6c. 8d. 9e. 1

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152 views help_outlineImage TranscriptioncloseIndicate the answer choice that best comple tes the statement or answers the question. 1. The electron in a hydrogen atom, originally in level photon of wavelength 3745 nm. What is the final level of the electron? (c-3.00x108 m/s, h=6.63x10-34 J.s, R 2.179x10-18 J) 8, undergoes a transition to a lower level by emitting a a. 5 b. 6 c. 8 d. 9 e. 1 fullscreen
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Step 1

The Rydberg’s formula for an electron changing its energy level by emitting a photon of a particular wavelength is shown as follows: help_outlineImage Transcriptionclose1 = R is the wavelength of light emitted. Ry is Rydberg's constant is equal to 1.097x 10' m1. n and n are the final and initial level of an electron respectively fullscreen
Step 2

The above formula can be modified for convenience because the original formula doesn’t consider energy change directly.

Therefore, the modified Rydberg’s formula for an electron changing its energy level by emitting a photon of a particular wavelength is shown as follows: help_outlineImage Transcriptionclose1 AE = Rg (1) AE is the amount of energy change during the transition R is Rydberg's constant is equal to 2.179x1018 J. n and n are the final and initial level of an electron respectively fullscreen
Step 3

The Planck-Einstein relation between the energy of the ph... help_outlineImage TranscriptioncloseAE hv (2) AE is the energy change between two states. h is Planck's constant v is the frequecy. fullscreen

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